Question

suppose 60% of kids who visit a doctor have a fever, and 20% of kids with a fever have sore throats. what's the probability that a kid who goes to the doctor has a fever and a sore throat? rounded to three decimal places as needed.

Answer 1

Answer:

0.12

Step-by-step explanation:

Suppose there are 100 kids

60% have fever, so what is 60% of 100?

We convert percentage to decimal and multiply:

60/100 = 0.6

0.6 * 100 = 60 have fever

20% of the people having fever (60 of them) have sore throats, so,

What is 20% of 60?

We convert percentage to decimal and multiply:

20/100 = 0.2

0.2 * 60 = 12 have sore throat

So, how many people are there with fever AND sore throat, that is 12. We took initially there to be 100 people. Hence, the probability is:

$\frac{12}{100}=0.12$