4(3+14c−12d)
=(4)(3+14c+−12d)
=(4)(3)+(4)(14c)+(4)(−12d)
=12+c−2d
=c−2d+12
Answer: No
Step-by-step explanation:
This is not an isosceles triangle because there are different angle measurements. The rule of an isosceles triangle is that it must always have two equal sides and angles.
Step-by-step explanation:
please sorry to barge into your question without any reasonable answer all I want to say is that this is a graph and I think that the domain and range this is increasing to calculate like the unit for example you have - 9 and - 3 you should calculate how many units are between -9 and -2 I'm not sure and I just really need marks now point where I can get on with my procedure so sorry for just barging in like that I'm so sorry
Recall some identities:
tan(x) = sin(x) / cos(x)
cos(x + y) = cos(x) cos(y) - sin(x) sin(y)
cos(x - y) = cos(x) cos(y) + sin(x) sin(y)
sin(x - y) = sin(x) cos(y) - cos(x) sin(y)
This means we have
• cos²(90° - x) = [cos(90°) cos(x) + sin(90°) sin(x)]²
… = sin²(x)
• tan(180° - x) = sin(180° - x) / cos(180° - x)
… = [sin(180°) cos(x) - cos(180°) sin(x)] / [cos(180°) cos(x) + sin(180°) sin(x)]
… = sin(x) / (-cos(x))
… = -tan(x)
(and we also get sin(180° - x) = sin(x))
• cos(180° + x) = cos(180°) cos(x) - sin(180°) sin(x)
… = -cos(x)
So, the given expression reduces to
sin²(x) (-tan(x)) (-cos(x)) / sin(x) = sin²(x)
since tan(x) and cos(x)/sin(x) = 1/tan(x) will cancel.
