$(x+3)^{\frac{1}{2} } -1=x\\(x+3)^{\frac{1}{2} } =x+1\\squaring\\x+3=x^2+2x+1\\\\x^{2} +2x-x+1-3=0\\x^2+x-2=0\\x^2+2x-x-2=0\\x(x+2)-1(x+2)=0\\(x+2)(x-1)=0\\x=-2,1$

8 0

2 years ago

Which of the following is a composite number? A. 91 B. 29 C. 139 D. 13

alexdok [17]

91 is a composite number because has more than 3 factors, which include 13 and 7. Hope this helped!

4 0

2 years ago

If f(x) = log2 (x + 1), what is f-1(2)? (2 points)

Soloha48 [4]

as you already know, to get the inverse of any expression, we start off by doing a quick switcheroo on the variables, and then solve for "y".

$\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{f(x)}{y}=\log_2(x+1)\implies \stackrel{\textit{quick switcheroo}}{\underline{x}=\log_2(\underline{y}+1)}\implies 2^x=2^{\log_2({y}+1)} \\\\\\ 2^x=y+1\implies 2^x-1=\stackrel{f^{-1}(x)}{y} \\\\[-0.35em] ~\dotfill\\\\ 2^2-1=f^{-1}(2)\implies 3=f^{-1}(2)$

3 0

2 years ago

Read 2 more answers

work out the equation of the line which passes through the point (-1, 2) and is paralell to the line y = x + 4

notka56 [123]

Step-by-step explanation:

working g and everything is above

hope its of help

3 0

2 years ago