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3 years ago

Write the expression in standard form. five divided by quantity three minus fifteen i.

1 answer:

5 0

Standard form is a+bi where a and b are real numbers
remeber that i²=-1

ok

$\frac{5}{3-15i}$
we got to get the i out of the denomenator
remember the differnce of 2 perfect squares where (a-b)(a+b)=a²-b²

so multiply the whole thing by $\frac{3+15i}{3+15i}$
we get
$\frac{5(3+15i)}{3^2-(15i)^2}=\frac{15+75i}{9-225(-1)}=\frac{15+75i}{9+225}=$ $\frac{15+75i}{234}=\frac{15}{234}+\frac{75i}{234}=\frac{15}{234}+\frac{75}{234}i=\frac{5}{78}+\frac{25}{78}i$

in standard form, it is $\frac{5}{78}+\frac{25}{78}i$

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Hans is staining the wooden floor of a court. The court is in the shape of a rectangle. Its length is feet and its width is feet

Tomtit [17]

Answer:

number of cans Raina will be needed in court floor is 14 cans

Step-by-step explanation:

CHECK THE COMPLETE QUESTION BELOW;

Raina is staining the wooden floor of a court. The court is in the shape of a rectangle. Its length is 46 feet and its width is 35 feet. Suppose each can of wood stain covers 115 square feet. How many cans will she need to cover the court?

CALCULATION;

Given:

length of the rectangular shape =46 feet

width of the the rectangular shape = 35 feet.

The floor of the court room is having a rectangular shape, then we need to calculate the surface Area of the rectangular shape first in order to know the number of cans that Raina will be needed

Surface Area= Length × Width

= 46feet × 35 feet

=1610 square ft

Then to get the number of cans , we need to divide the surface Area by each can of wood stain covers which is 115 square feet,

number of cans Raina will be needed in court = 1610 square ft / 115 square ft = 14

number of cans Raina will be needed in court floor is 14cans

7 0

3 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago

About how much would it have cost

Anton [14]

It would cost about $.50 because $8.15 rounds to $8.00, and 8/16 = 0.5

4 0

2 years ago

Read 2 more answers

The Eco Pulse survey from the marketing communications firm Shelton Group asked individuals to indicate things they do that make

BabaBlast [244]

Answer:

a) 0.54 = 54% probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both.

b) 0.46 = 46% probability that a randomly selected person will not feel guilty for either of these reasons

Step-by-step explanation:

We use Venn's Equations for probabilities.

I am going to say that:

P(A) is the probability that a randomly selected person will feel guilty about wasting food.

P(B) is the probability that a randomly selected person will feel guilty about leaving lights on when not in a room.

0.12 probability that a randomly selected person will feel guilty for both of these reasons.

This means that $P(A \cap B) = 0.12$

0.27 probability that a randomly selected person will feel guilty about leaving lights on when not in a room.

This means that $P(B) = 0.27$

0.39 probability that a randomly selected person will feel guilty about wasting food

This means that $P(A) = 0.39$

a. What is the probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both (to 2 decimals)?

$P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.39 + 0.27 - 0.12 = 0.54$

0.54 = 54% probability that a randomly selected person will feel guilty for either wasting food or leaving lights on when not in a room or both.

b. What is the probability that a randomly selected person will not feel guilty for either of these reasons (to 2 decimals)?

$p = 1 - P(A \cup B) = 1 - 0.54 = 0.46$

0.46 = 46% probability that a randomly selected person will not feel guilty for either of these reasons

8 0

3 years ago

Find the area in the right tail more extreme than z= 3.01 in a standard normal distribution

Feliz [49]

The area in the right tail more extreme than z= 3.01 in a standard normal distribution is given by

P(z > 3.01) = 1 - P(z < 3.01) = 1 - 0.99869 = 0.00131

5 0

3 years ago