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3 years ago

24x-9 solve A 3(8x - 9) B 6(4x - 9)

Mathematics

1 answer:

Hitman42 [59]3 years ago

8 0

24 x -9 or 24x - 9?
then I will answer :))

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Express using algebra. Five more than twice x.

Anarel [89]

Answer:

2x+ 5

Step-by-step explanation:

5 0

3 years ago

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If x varies inversely as the square of y and if x=3 when y=-1, what is the value of x when y =3

lyudmila [28]

Answer:

$x$ would be $(1/3)$ when $y = 3$ .

Step-by-step explanation:

The question states that $x$ varies "inversely" as $y^2$ . In other words, there is a non-zero number $a$ (a constant) such that:

$\displaystyle x = \frac{a}{y^2}$ .

The challenging part is to find the value of $a$ in this equation.

Given that $x = 3$ when $y = -1$ , replace the $x$ in this equation with $3$ and $y$ with $(-1)$ . This equation should still be valid:

$\displaystyle 3 = \frac{a}{(-1)^{2}}$ .

Solve for $a$ :

$a = 3 \times (-1)^2 = 3$ .

Hence, the relation between $x$ and $y$ becomes:

$\displaystyle x = \frac{3}{y^2}$ .

Find the value of $x$ when $y = 3$ by replacing the $y$ in this equation with $3$ .

$\displaystyle x = \frac{3}{3^2} = \frac{1}{3}$ .

In other words, the value of $x$ would be $\displaystyle \frac{1}{3}$ when $y = 3$ .

7 0

3 years ago

Brainliest to whoever can answer this for me

boyakko [2]

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3 years ago

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Find the measure of the angle

zheka24 [161]

Answer:

Step-by-step explanation:

The triangle shown is an isoceles triangle. This means that there are two congruent base angles and a vertex angle. In this case, angle X and angle Y are the base angles, so we can set up an equation to first find the value of t.

5t - 13 = 3t + 3

2t - 13 = 3 (Subtract 3t from both sides)

2t = 16 (Add 13 to both sides)

t = 8 (Divide both sides by 2)

Now that we have the value of t, we can plug it back in to the expression for angle X to find its measure.

5(8) - 13

40 - 13

So, the measure of angle X is 27

6 0

3 years ago

Find the solution to dy/dt = 7 y<br><br> satisfying<br> y(9) = 5

AVprozaik [17]

$\rm \dfrac{dy}{dt}=7y,\qquad\qquad\qquad y(9)=5$

I'm not sure what methods you've learned up to this point but one option is to apply separation of variables:

$\rm \dfrac{dy}{y}=7dt$

and then integrate from there,

$\rm ln|y|=7t+c$

exponentiate to isolate y,

$\rm |y|=e^{7t+c}$

Apply exponent rule,

$\rm |y|=e^c e^{7t}$

rename this e^c as some new constant, perhaps A,

$\rm \pm y=A e^{7t}\qquad\qquad A>0$

This A can only be positive, non-zero, but absorbing the plus/minus fixes that restriction,

$\rm y=A e^{7t}\qquad\qquad A\ne0$

Use your initial information to solve for this unknown value A,

$\rm y(9)=A e^{7\cdot9}=5$

solving for A, dividing by the exponential,

$\rm A=5e^{-63}$

So we get a final result of

$\rm y(t)=5e^{-63}e^{7t}$

apply exponent rule again to get a better looking answer, and factor,

$\rm y(t)=5e^{7(t-9)}$

Lemme know if too confusing.

3 0

3 years ago