How would I put this into a solvable equation, m= ak/n?

Mathematics

1 answer:

12345 [234]1 year ago

7 0

The given equation is

m = ak/n

We want to solve for k

The first step is to multiply both sides of the equation by n. We have

m * n = ak/n * n

mn = ak

The next step is to divide both sides of the equation by a. We have

mn/a = ak/a

mn/a = k

k = mn/a

The correct option is the second one

You might be interested in

The masses mi are located at the points pi. find the moments mx and my and the center of mass of the system. m1 = 2, m2 = 5, m3

creativ13 [48]

Most graphing calculators will do weighted averages pretty easily. It is mostly a matter of data entry.

mx = -2
my = 10
(x, y) = (mx, my)/10 = (-0.2, 1)

6 0

3 years ago

A Venn diagram is shown below:

mina [271]

(A ∩ B) means "A intersection B". Your problem statement tells you the intersection contains
{3, 4}

6 0

3 years ago

Read 2 more answers

Movie rental at a video store, you have two options for renting movies. You can pay $4 per movie,or you can pay a one time membe

VikaD [51]

The answer is nine movie rentals. 9×1.5+20 equals less than 9×4 which equals 36. I hope that answerd your question ☺️☺️

7 0

3 years ago

What is the range

Elena-2011 [213]

C I believe the -2 part that was the one just looked it up on google XD hope it helped

7 0

3 years ago

2 3/8 - 4 1/2 + 3 1/8 - (1/2)

UkoKoshka [18]

let's convert the mixed fractions to improper fractions firstly.

$\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill$

$\bf \cfrac{19}{8}-\cfrac{9}{2}+\cfrac{25}{8}-\cfrac{1}{2}\implies \stackrel{\textit{using an LCD of 8}}{\cfrac{(1)19-(4)9+(1)25-(4)1}{8}}\implies \cfrac{19-36+25-4}{8} \\\\\\ \cfrac{4}{8}\implies \cfrac{1}{2}$

8 0

3 years ago