Jonathan parents told him that for every 5 hours of homework or reading he completed

which of the following are right triangles: a triangle with side lenghts 6 inches, 8 inches,10 inches, a triangle with side leng

amid [387]

9514 1404 393

Answer:

(6, 8, 10) right
(8, 15, 17) right
(5, 12, 13) right

Step-by-step explanation:

It can be helpful to memorize a few of the Pythagorean triples that show up in Algebra problems. Their multiples also form right triangles.

(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17), (9, 40, 41)

The triple (6, 8, 10) is the first one of these, multiplied by 2 inches.

The only triple that is a sequence of consecutive integers is (3, 4, 5), so you know immediately that (4, 5, 6) does not form a right triangle.

Of course, you can check any of them to see if the squares of the smaller two numbers total the square of the larger number:

4² +5² = 16 +25 = 41 ≠ 6² . . . . . (4, 5, 6) is not a right triangle

5 0

2 years ago

How to solve (2.31*10^-6)+(5.87*10^-4)

S_A_V [24]

We want to calculate the following

$2.31\cdot10^{-6}+5.87\cdot10^{-4}$

Using the properties of exponents, we have that

$10^{-6}=10^{-4}\cdot10^{-2}$

So we have

$2.31\cdot10^{-6}+5.87\cdot10^{-4}=2.31\cdot10^{-2}\cdot10^{-4}+5.87\cdot10^{-4}$

So, if factor 10^-4 on the right side, we have

$10^{-4}(2.31\cdot10^{-2}+5.87)$

Note that

$2.31\cdot10^{-2}=0.0231$

Then,

$5.87+2.31\cdot10^{-2}=5.87+0.0231=5.8931^{}$

So we have that

$2.31\cdot10^{-6}+5.87\cdot10^{-4}=5.8931\cdot10^{-4}$

5 0

1 year ago

Q5 Q3.) How far, to the nearest foot, is the ship from the statue's base?

dusya [7]

Distance from base = 305 / tan(29.5deg)
= 539 ft

7 0

2 years ago

7x-11=5(x-2)+2x-1= ?

yan [13]

0 = 0

Simplifying
7x + -11 = 5(x + -2) + 2x + -1

Reorder the terms:
-11 + 7x = 5(x + -2) + 2x + -1

Reorder the terms:
-11 + 7x = 5(-2 + x) + 2x + -1
-11 + 7x = (-2 * 5 + x * 5) + 2x + -1
-11 + 7x = (-10 + 5x) + 2x + -1

Reorder the terms:
-11 + 7x = -10 + -1 + 5x + 2x

Combine like terms: -10 + -1 = -11
-11 + 7x = -11 + 5x + 2x

Combine like terms: 5x + 2x = 7x
-11 + 7x = -11 + 7x

Add '11' to each side of the equation.
-11 + 11 + 7x = -11 + 11 + 7x

Combine like terms: -11 + 11 = 0
0 + 7x = -11 + 11 + 7x
7x = -11 + 11 + 7x

Combine like terms: -11 + 11 = 0
7x = 0 + 7x
7x = 7x

Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 7x + -7x

Combine like terms: 7x + -7x = 0
0 = 0

Solving
0 = 0

3 0

2 years ago

Every prime number greater than 10 has a digit in the ones place that is include in wich set of numbers A- 1,3,7,9 B-1,3,5,9 D-1

marta [7]

That's very interesting. I had never thought about it before.
Let's look through all of the ten possible digits in that place,
and see what we can tell:

-- 0:
   A number greater than 10 with a 0 in the units place is a multiple of
   either 5 or 10, so it's not a prime number.

-- 1:
    A number greater than 10 with a 1 in the units place could be
    a prime (11, 31 etc.) but it doesn't have to be (21, 51).

-- 2:
   A number greater than 10 with a 2 in the units place has 2 as a factor
   (it's an even number), so it's not a prime number.

-- 3:
   A number greater than 10 with a 3 in the units place could be
   a prime (13, 23 etc.) but it doesn't have to be (33, 63) .

-- 4:
   A number greater than 10 with a 4 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 5:
   A number greater than 10 with a 5 in the units place is a multiple
   of either 5 or 10, so it's not a prime number.

-- 6:
   A number greater than 10 with a 6 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 7:
   A number greater than 10 with a 7 in the units place could be
   a prime (17, 37 etc.) but it doesn't have to be (27, 57) .

-- 8:
   A number greater than 10 with a 8 in the units place is an even
   number, and has 2 as a factor, so it's not a prime number.

-- 9:
   A number greater than 10 with a 9 in the units place could be
   a prime (19, 29 etc.) but it doesn't have to be (39, 69) .

So a number greater than 10 that IS a prime number COULD have
any of the digits 1, 3, 7, or 9 in its units place.

It CAN't have a 0, 2, 4, 5, 6, or 8 .

The only choice that includes all of the possibilities is 'A' .

4 0

2 years ago