/* package whatever; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;
class NestedLoops {
public static void main (String [] args) {
int numRows = 4;
int numCols = 5;
int i,j;
char ch = 'A';
// Note: You'll need to declare more variables
/* Your solution goes here */
for ( i = 0; i < numRows; i++) { // Outer loop runs for numRows times
for ( j = 0; j < numCols; j++) { // Inner loop runs for numCols times
System.out.print(i+1);
System.out.print((char)(ch+j));
System.out.print(" ");
}
}
System.out.println("");
return;
}
}
Answer:
Resource Ownership and Scheduling execution
Explanation:
In process characteristic the characteristic is
- Resource ownership
- Scheduling / Execution
In Resource ownership, the OS performs a protection function where unwanted interference in processes are with resources
In scheduling execution, the process has execution state and scheduled. They can be separated by resource ownership.
The dispatching of the process is the lightweight process, and it is multi-threading. The ability of the operating system supports the single concurrent process.
The process is a unit in the resource protection and protected the CPU and other processes. It contains the multiple thread execution
Each thread contains the running, ready state and saved the thread context and access the memory. Some necessary activities of the various threads are the same address space and the resources.
Search terms.
I hope you like this, please Brainliest me, and have a wonderful night! :D
Answer:
The answer to this question can be described as follows:
Explanation:
Given data:
Performance of the CPU:
The Fastest Factor Fraction of Work:
Current Feature Speedup:
1.5
CPU upgrade=6000
Disk activity:
The quickest part is the proportion of the work performed:
Current Feature Speedup:
Disk upgrade=8000
System speedup formula:
Finding the CPU activity and disk activity by above formula:
CPU activity:
Disk activity:
CPU:
Formula for CPU upgrade:
DISK:
Formula for DISK upgrade:
equation (3) and (4),
Thus, for the least money the CPU alternative is the best performance upgrade.
b)
From (3) and (4) result,
The disc choice is therefore the best choice for a quicker system if you ever don't care about the cost.
c)
The break-event point for the upgrades:
=4702.19 x-0.5
= -2351.095
From (2) and (3))
Therefore, when you pay the sum for disc upgrades, all is equal $ -2351.095
