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Answer:
/*
Find Largest and Smallest Number in an Array Example
This Java Example shows how to find largest and smallest number in an
array.
*/
public class FindLargestSmallestNumber {
public static void main(String[] args) {
//array of 10 numbers
int numbers[] = new int[]{32,43,53,54,32,65,63,98,43,23};
//assign first element of an array to largest and smallest
int smallest = numbers[0];
int largetst = numbers[0];
for(int i=1; i< numbers.length; i++)
{
if(numbers[i] > largetst)
largetst = numbers[i];
else if (numbers[i] < smallest)
smallest = numbers[i];
}
System.out.println("Largest Number is : " + largetst);
System.out.println("Smallest Number is : " + smallest);
}
}
/*
Output of this program would be
Largest Number is : 98
Smallest Number is : 23
*/
Explanation:
I would say the primary Beni fit is more space for storage , but also it does effect the speed eventually. If your hard drive is almost full, everything will be slower
No. If it is cracked or damaged THROW IT AWAY. I can tell you from personal experience, not much worse than a wheel breaking apart while spinning and embedding chunks of the wheel in your chest and face.
Answer:
for(int i =0; i<yearlySalesTotals.length;i++)
Explanation:
The for statement in has the syntax as given above, it has an int variable indicating the starting index, then a boolen condition ensuring that you don't get out of the array bounds, and an increment operator.
See below a complete program in java that will output all elements of the array assuming the array yearlySalesTotals contains only ten elements and all indexes has been assigned values.
public class ANot {
public static void main(String[] args) {
double []yearlySalesTotals = new double[10];
for(int i = 0; i<yearlySalesTotals.length; i++){
System.out.println(yearlySalesTotals[i]);
}
}
}