Recall that carotene and xanthophyll have very similar molecular structures except for the presence of two hydroxide groups in x
anthophyll. Use this information to explain the difference in Rf values for these two pigments given the substrate/solvent combination employed in this exercise.
In the event that an alternate dissolvable were utilized, the Rf worth would not be the equivalent on the grounds that, contingent upon the dissolvable, there is a distinction in dissolvability. On the off chance that an alternate dissolvable was utilized, the general places of the groups would be different.
The Rf estimation of the xanthophyll is 66% that of carotene since xanthophyll has a H bond with cellulose, which backs it off, and makes it less dissolvable in the dissolvable.
Carotene is progressively dissolvable in 9:1 oil ether CH3)2CO arrangement, which made it be conveyed higher and have a bigger Rf value.
Measure the separation the dissolvable voyaged, which is Df, and measure the separation the test arrangement voyaged, which is Ds.
Ascertain the maintenance factor utilizing this condition <em>RF = Ds/Df. </em>
Basically isolate the separation the arrangement went by the separation the solvent traveled.
<u>The cell lacks a nucleus.</u> We know this because prokaryotes are single celled organisms that lack a membrane bound nucleus or membrane bound organelles. So, looking under the microscope, you'd notice that the cell has no distinct nucleus, which immediately helps us find the answer we're looking for.
