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Tems11 [23]
4 years ago
7

A population of lizards lives in an isolated area where local rocks contain a high concentration of radioactive elements. A stud

y of this population would MOST LIKELY show A) a lower than average mutation rate. B) a higher than average mutation rate. Eliminate C) a higher survival rate than other lizard populations. D) an increase in size compared to other lizard populations.
Biology
1 answer:
Tems11 [23]4 years ago
5 0
B.

The radiation present is likely to cause genetic mutations. 
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2. Wolves have genes that give them a very powerful sense of smell much more
PIT_PIT [208]

Answer:

A good example may be represented by different shapes and sizes of beaks in finches living on different Galapagos islands

Explanation:

According to the evolutionary theory proposed by Darwin, natural selection is a mechanism that acts on heritable phenotypic variation among individuals within a population. Genetic variation can be considered as the primary source of heritable phenotypic variation. Those organisms that are better adapted for a particular environment will have more chances to survive and reproduce, thereby passing these heritable traits to the next generation. For example, during his work, Darwin observed that the shape and size of beaks in finch species from different islands in the Galapagos archipelago varied as a consequence, i.e., as an adaptation, to the availability of food resources present in each island.

5 0
3 years ago
A plant breeder has determined the following variances for yield of corn in his fields:
Law Incorporation [45]

Answer:

A. VG = 80

B. Broad sense heritability = 0.80

C. Narrow sense heritability = 0.30

D. Average yield = 430 Units

Explanation:

A. Given that

VA = 30

VD = 50

VI = assumed not available

Therefore

Total genetic variance (VG) = VA + VD

= 30 + 50

= 80

VG = 80

B. Given that

VP = 100

VG = 80

Broad sense heritability, H2 = VG/VP

= 80/100

= 0.80

C. Given that

VA = 30

VP = 100

Narrow sense heritability, h2 = VA/VP

=30/100

= 0.30

D. The difference in selection = 500 - 400

= 100

Recall,

Selection response is heritability multiplied by selection differential.

That is

R = h2S

Selection differential = 100

Heritability h2 = 0.30

Selection response = 0.30 × 100

= 30units

Therefore, expected average yield = 400 + 30

= 430 Units

6 0
3 years ago
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