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3 years ago

R-18=27 solve the equations shown above

Mathematics

1 answer:

Annette [7]3 years ago

7 0

Answer:

putaputaputaputaputaputa

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A guy wire attached to the top of a radio antenna is anchored to a point on the ground 20 m from the antenna's base. If the wire

gregori [183]

Answer:

the cosine of the angle equals 40.0 m divided by the length of the wire

cos(58º20') = 40.0 m / L

L = 40.0 m / cos(58º20')

Step-by-step explanation:

6 0

3 years ago

You originally draw a design for an art contest on a 2 in. x 5 in. card. The second phase of the contest requires the drawing to

Licemer1 [7]

Answer:

the other dimension is 4.2 inches

Step-by-step explanation:

The scale factor from 5 inches to 10.5 inches is ...

10.5/5 = 2.1

Then the other dimension is 2 inches times that scale factor:

2.1×(2 in) = 4.2 in

4 0

3 years ago

Find the volume of the solid bounded by z = 2 - x2 - y2 and z = 1. Express your answer as a decimal rounded to the hundredths pl

butalik [34]

Answer:

The answer is " $(\frac{\pi}{2})$ ".

Step-by-step explanation:

$z = 2 - x^2 - y^2.........(1) \\\\z = 1.............(2)$

Let add equation 1 and 2:

Using formula: $x^2+y^2=1 \\\\$

convert to polar coordinates

$r=2$

$\theta \varepsilon (0=\pi)=z\\\\V=\int^{2\pi}_{\theta=0}\int^{1}_{\pi=0}\int^{z_{2}}_{z_1} r \ dr \d \theta\\\\$

$=\int^{2\pi}_{0}\int^{1}_{0} (Z_2-z_1)r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} 1- (-1-x^2-y^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (+1 \pm r^2) r \ dr \d \theta\\\\=\int^{2\pi}_{0}\int^{1}_{0} (-r^3 + r) \ dr \d \theta\\\\=\int^{2\pi}_{0} (-\frac{r^4}{4}+\frac{r^2}{1})^{1}_{0} \d \theta\\\\=\int^{2\pi}_{0} (\frac{1}{4}) \d \theta\\\\=(\frac{2 \pi}{4}) \\\\=(\frac{\pi}{2}) \\\\$

8 0

3 years ago

The perimeter of the patio is 64 feet. The width of the patio is (x+2) feet and the length of the patio is (x+6) feet. What are

ValentinkaMS [17]

The formula for the perimeter is P = 2w + 2l, where w is the width and l is the length. It is given that the width = (x+2) and the length = (x+6). Therefore, we can make this equation:

P = 2w + 2l

64 = 2(x+2) + 2(x+6) ⇒ Distributive property

⇒ 64 = 2x + 4 + 2x + 12 ⇒ Combine like terms

⇒ 64 = 4x + 16 ⇒ Subtract 16 from both sides

⇒ 48 = 4x ⇒ Divide both sides by 4

⇒ x = 12

Then, we use x = 12 and substitute it in to find the length and width

Width = (x+2) = (12+2) = 14

Length = (x+6) = (12+6) = 18

The dimensions of the patio is 14 by 18

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3 years ago

Solving Simultaneously equations 3. 2x + 3y = 1 -x + 2y = - 4

enot [183]

Answer:

2x5y7

Step-by-step explanation:

7 0

3 years ago

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