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Serggg [28]
2 years ago
13

The perimeter of the patio is 64 feet. The width of the patio is (x+2) feet and the length of the patio is (x+6) feet. What are

the dimensions of the patio?
Mathematics
1 answer:
ValentinkaMS [17]2 years ago
5 0

The formula for the perimeter is P = 2<em>w</em> + 2<em>l</em>, where <em>w</em> is the width and <em>l</em> is the length. It is given that the width = (x+2) and the length = (x+6). Therefore, we can make this equation:

P = 2<em>w</em> + 2<em>l</em>

64 = 2(x+2) + 2(x+6) ⇒ Distributive property

⇒ 64 = 2x + 4 + 2x + 12 ⇒ Combine like terms

⇒ 64 = 4x + 16 ⇒ Subtract 16 from both sides

⇒ 48 = 4x ⇒ Divide both sides by 4

⇒ x = 12

Then, we use x = 12 and substitute it in to find the length and width

<em>Width</em> = (x+2) = (12+2) = 14

<em>Length</em> = (x+6) = (12+6) = 18

The dimensions of the patio is <u>14 by 18</u>

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P(T>8300000)=1-P(T

Step-by-step explanation:

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Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

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