Answer:
69.14% probability that the diameter of a selected bearing is greater than 84 millimeters
Step-by-step explanation:
According to the Question,
Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.
- In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ
we have μ=87 , σ=6 & X=84
- Find the probability that the diameter of a selected bearing is greater than 84 millimeters
This is 1 subtracted by the p-value of Z when X = 84.
So, Z = (84-87)/6
Z = -3/6
Z = -0.5 has a p-value of 0.30854.
⇒1 - 0.30854 = 0.69146
- 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.
Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)
The last one is correct answer
ANSWER:
V= 3,619.1 km^3
EXPLANATION:
Simply plug in the radius (12 km) and height (24 km) into the cone volume formula.
Answer:
$9600 saving / year
Step-by-step explanation:
1/5 of $21000 = 21000 / 5 = $4200 / month on rent
3/7 of $21000 = (21000 / 7) x 3 = $9000 / month on food (shocking right :) food is expensive)
1/3 of $21000 = 21000 / 3 = $7000 on other expenses / month
total savings/month = salary/month - rent/month - food/month - other expenses/month
total savings/month = 21000 - 4200 - 9000 - 7000
total savings/month = $800
<u><em>BUT</em></u> the question asks for savings per year. therefore, we must multiply the savings per month by total months per year (12)
800 x 12 = $9600
the person's total savings per year, with a salary of $21000 per month, is equal to $9600 per year
The answer would be 1.25.
