Answer: 4
Step-by-step explanation:
The functions are illustrations of composite functions.
<em>The soil temperature at 2:00pm is 67</em>
The given parameters are:
---- the function for sun intensity
-- the function for temperature
At 2:00pm, the value of h (number of hours) is:


Substitute 8 for h in
, to calculate the sun intensity



Substitute 8/9 for I in
, to calculate the temperature of the soil



Approximate

Hence, the soil temperature at 2:00pm is 67
Read more about composite functions at:
brainly.com/question/20379727
Answer:
slope of the first line: 1
slope of the second line: 0.778
slope of the third line: 0.375
slope of the fourth line: 1.25
Step-by-step explanation:
Given two points (x1, y1) and (x2, y2), the slope of a line is computed as follows:
slope = (y2 - y1)/(x2 - x1)
Therefore,
slope of the first line: [5 - (-4)]/[4 - (-5)] = 1
slope of the second line: [5 - (-2)]/[4 - (-5)] = 0.778
slope of the third line: [2 - (-1)]/[3 - (-5)] = 0.375
slope of the fourth line: [5 - (-5)]/[4 - (-4)] = 1.25
sdfsdf
4) 
Multiply by 2 on both sides
3m + 15 = 45
Subtract both sides by 15
3m = 30
Divide both sides by 3
so m = 3
5) 
Multiply both sides by 8
168 = q + 35
Subtract both sides by 35
q = 133
6) 
Subtract 14 from both sides

multiply by -11 on both sides
4x = 572
Divide both sides by 4
x= 143
7) 
Add 6 on both sides

Multiply both sides by 5
3c = 75
Divide both sides by 3
c = 25
8) 
Subtract both sides by 17

Multiply both sides by -2
t = -52
9) 
Multiply both sides by -7
42= 5p + 2
subtract 2 from both sides
40 = 5p
Divide both sides by 5
so p = 8
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130
