Answer:
7
Step-by-step explanation:
Answer: B (-12, 15)
Step: (3×-4) =-12
And (3×5)= 15
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
{x | x = –5, –3, 1, 2, 6}
Step-by-step explanation:
The domain is the list of first-values of the ordered pairs:
{x | x = –5, –3, 1, 2, 6}
The line of reflection is b
You can see it much easier if take away all the clutter. Redraw the diagram and take way a d and especially c.
You should be left with only line b and the two triangles. You can see it much easier if you do that. Then just look at the parallel lines of the triangles. They are right across from each other.
