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3 years ago

Which graph shows the solution to the inequality -3x-7<20

Mathematics

2 answers:

Inessa05 [86]3 years ago

8 0

Answer:

$x>-9$

Step-by-step explanation:

$-3x-7$

Solve the inequality for x

To get rid of -7, add 7 on both sides

$-3x-7$

$-3x$

now we divide both sides by -3. Whenever we divide by any negative number we flip the inequality sign

$x>-9$

We use number line

x is greater than -9. So we shade the number line to the right of -9

Use open circle at -9 and shade to the right.

Anestetic [448]3 years ago

6 0

Answer:

-9 < x

Step-by-step explanation:

-3x - 7 < 20

+ 7 + 7

___________

-3x < 27

___ ___

-3 -3

x > -9 [Whenever you divide or multiply by a negative, reverse the inequality symbol.]

The above answer is written in reverse, which is the exact same result.

I am joyous to assist you anytime.

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2 years ago

A sign id front of a roller coaster says "You must be 40 inches tall to ride." What percentage of this height is:

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85%

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4 0

3 years ago

The table shows a proportional relationship between the mass, in kilograms

OlgaM077 [116]

Answer:

C) Dog: 40 kg, Medicine: 1.6 mL

D) Dog: 35 kg, Medicine: 1.4 mL

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Let

x ---> the mass, in kilograms of a dog

y ---> milliliters of flea medicine a veterinarian prescribes

Find the value of the constant of proportionality k for the given data

$k=\frac{y}{x}$

For x=50 kg, y=2 mL ----> $k=\frac{2}{50}=0.04\ mL/kg$

For x=10 kg, y=0.4 mL ----> $k=\frac{0.4}{10}=0.04\ mL/kg$

For x=5 kg, y=0.2 mL ----> $k=\frac{0.2}{5}=0.04\ mL/kg$

The linear direct equation is equal to

$y=0.04x$

Verify each choice

A) Dog: 15 kg, Medicine: 0.9 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

$\frac{0.9}{15}= 0.06\ mL/kg$

$0.06 \neq 0.04$

therefore

These numbers could not be used as the missing values in the table

B) Dog: 25 kg, Medicine: 0.8 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

$\frac{0.8}{25}= 0.032\ mL/kg$

$0.032 \neq 0.04$

therefore

These numbers could not be used as the missing values in the table

C) Dog: 40 kg, Medicine: 1.6 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

$\frac{1.6}{40}= 0.04\ mL/kg$

$0.04 = 0.04$

therefore

These numbers could be used as the missing values in the table

D) Dog: 35 kg, Medicine: 1.4 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

$\frac{1.4}{35}= 0.04\ mL/kg$

$0.04 \neq 0.04$

therefore

These numbers could be used as the missing values in the table

E) Dog: 20 kg, Medicine: 1.2 mL

Divide the milliliters of medicine by the kilograms of the dog and compare the result with the constant of proportionality

$\frac{1.2}{20}= 0.06\ mL/kg$

$0.06 \neq 0.04$

therefore

These numbers could not be used as the missing values in the table

5 0

3 years ago