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castortr0y [4]
4 years ago
7

Someone Please help me answer this question

Mathematics
1 answer:
ArbitrLikvidat [17]4 years ago
3 0

I think x=10 because alternate interior angles so I made the equation: x+54=6x+4

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19−6(−k+4) Simplify to create an equivalent expression
almond37 [142]

\text{Hey there!}\\\\\\\text{In order for you to solve this equation you need to distribute}\\\text{-6(-k) = 6k \& -6(4) = -24}\\\\\text{New equation: 19 + 6k + (-24)}\\\\\text{Combine your like terms (if there is any)}\\\text{(6k(19+(-24)))}\\\text{Your like terms are:  19  + (-24) = -5}

\text{Your new equation is: 6k + (-5)}\\\\\text{+ \&  -  =  -}\text{\underline{ (positive \& negative equals negative)}}\\\\\text{The number in the center will be a negative}\\\\\boxed{\boxed{\text{Answer: 6k - 5}}}\checkmark\\\\\\\\\\\text{Good luck on your assignment and enjoy your day!}\\\\\frak{LoveYourselfFirst:)}

8 0
3 years ago
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If f(x) = 3x - 1 and g(x) = x + 2 , find (f - g)(x)
ivolga24 [154]

Answer:

Answer D is the correct answer 4x+1

3 0
4 years ago
A boat leaves the harbor entrance and travels 28 miles in the direction N 43° E. The captain then turns the boat 90° and travels
Serga [27]

Answer:

Step-by-step explanation:

A boat leaves the harbor entrance and travels 28 miles in the direction N 43° E.

Displacement in vector form

= 28 cos43 i + 28sin43j

= 20.47 i + 19.1 j

The captain then turns the boat 90° and travels another 15 miles in the direction S 47° E

Displacement

= 15 cos47 i - 15 sin47 j

= 10.22 i - 10.97 j

Total displacement

= 20.47 i + 19.1 j + 10.22 i - 10.97 j

= 30.69 i - 8.13 j

Magnitude of displacement

= 31.75 miles

Angle with east direction

TanФ = - 8.13 / 30.69

Ф = 15 degree  south of east.

3 0
3 years ago
Which expressions are equivalent to -6+4q+(-6q)
enot [183]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
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Convert the following numbers of calories or
kap26 [50]

Answer:

  • 32.823 kJ
  • 190.4 kJ
  • 260.00 kJ
  • 180.012 kJ

Step-by-step explanation:

The conversion factor for food energy or thermochemical calorimetry* is ...

  1 calorie = 4.184 J

  1000 calorie = 4.184 kJ

__

a. 7845 cal = 7845·4.184 J = 32,823 J = 32.823 kJ

b. 4.55·10^4 cal = 4.55·10^4·4.184 J = 1.904·10^5 J = 190.4 kJ

c. 62.142 kcal = 62.142·4.184 kJ = 260.00 kJ

d. 43,024 cal = 43,024·4.184 J = 180,012 J = 180.012 kJ

_____

* The thermochemical calorie is defined in terms of the heat capacity of water. An international calorie of 4.1868 J is defined in terms of energy, without respect to the heat capacity of water.

6 0
4 years ago
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