Simplify the following expression (w^8)8

Find the area of the figure.

tekilochka [14]

Answer:

30 units^2

Step-by-step explanation:

7 0

3 years ago

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Find the 15th term in the following arithmetic sequence : 1, 6, 11, 16, ...

Gnoma [55]

Answer:

a₁₅ = 71

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 1 and d = 6 - 1 = 5 , then

a₁₅ = 1 + (14 × 5) = 1 + 70 = 71

7 0

3 years ago

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2x-5y=-28 find the value of y when x equals -19

nydimaria [60]

<h3>Question:</h3>

2x-5y=-28 find the value of y when x equals -19

<h3>Answer:</h3>

Y = - 2

<h3>Step-by-step explanation:</h3>

First you plug in -19 where x is 2(-19)-5y = -28

Remove parentheses -2 · 19-5y= -28

Multiply -2 by 19 -38-5y= -28

Add 38 to both sides -5y = 10

Divide both sides by -5 [tex]\frac{-5y}{-5} =\frac{10}{-5}[/tex

you will get -2 which is the answer.

Hope this helped!

8 0

4 years ago

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Triangle abc has the following vertices:

Illusion [34]

9514 1404 393

Answer:

no

Step-by-step explanation:

It is impossible to plot an equilateral triangle on a coordinate grid using integer coordinates. The given triangle may be close, but cannot be an equilateral triangle.

4 0

3 years ago

Please help me with this question

swat32

Answer:

<h3>• y is 10.9</h3><h3>• theta is 65.4°</h3><h3>• Alpha is 24.64°</h3><h3>• sin theta is 10.9/12</h3><h3>• COS theta is 5/12</h3><h3>• tan theta is 10.9/5</h3><h3>• csc theta is 12/10.9</h3><h3>• ces is 12/5</h3><h3>• cot theta is 5/10.9</h3>

Step-by-step explanation:

<h3>Solution 1</h3>

Using the Pythagorean theorem

c²= a² + b², where c is the hypotenuse , a And b are the sides.

12² = y² + 5²

144 = y² + 25

144 - 25 = y²

√119 = √y²

10.9 = y

<h3>Solution 2</h3>

Using SOH-CAH-TOA

COS theta = Adjacent/Hypothesis

COS theta = 5/12

COS theta = 0.417

theta = COS-1 0.417

theta = 65.4°

<h3>theta is 65.4°</h3>

<h3>Solution 3</h3>

We are dealing with right triangle and it sum is 90.

To find Alpha subtract theta for 90

Alpha = 90 - 65.4 = 24.64°

<h3>Therefore Alpha is 24.64°</h3>

<h3>Solution 4</h3>

Using SOH-CAH-TOA

sin theta = opposite/ hypotenuse

sin theta = 10.9/12

<h3>sin theta is 10.9/12</h3>

<h3>Solution 5</h3>

Using SOH-CAH-TOA

COS theta = Adjacent/Hypothesis

COS theta = 5/12

<h3>COS theta is 5/12</h3>

<h3>Solution 6</h3>

Using SOH-CAH-TOA

tan theta = opposite/adjacent

tan theta = 10.9/5

<h3>tan theta is 10.9/5</h3>

<h3>Solution 7</h3>

csc theta is the reciprocal of sin theta

csc theta = 12/10.9

<h3>csc theta is 12/10.9</h3>

<h3>solution 8</h3>

ces theta is the reciprocal of COS theta.

ces theta = 12/5

<h3>Solution 9 </h3>

cot theta is the reciprocal of tan theta

cot theta = 5/ 10.9

<h3>cot theta is 5/10.9</h3>

6 0

2 years ago

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