False
A arithmetic sequence is a sequence that has a difference of 2. We see that we have -17 ... and then we have 2 ... and then 21. There is NOT a difference of 2, as we can see. Therefore, yiur answer would be (false).
<h3>
Answer:</h3>
A net is shown with 3 rectangles attached side by side all with width 2 centimeters. The length of the first and third rectangle is 9 centimeters and the middle is 7 centimeters. Attached to the middle rectangle below are 3 rectangles with a length of 7 centimeters. The width of these rectangles are 9 centimeters, 2 centimeters, and 9 centimeters.
<h3>
Step-by-step explanation:</h3>
The area of a rectangular prism is the area of 6 surfaces. That is, 3 pairs of surfaces. Each of the three pairs will have one of the sets of dimensions ...
- length × width
- length × height
- width × height
In order for a net to be a net useful for calculating the prism surface area, it must have 3 pairs of rectangles with these dimensions. The description above matches that requirement.
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Please note that no two surfaces with the same pair of dimensions are adjacent.
<u><em>3×10=30+1=31 is the true meaning and answer for this question.</em></u>
<u><em>Hope you good times!</em></u>
Answer:
GI = 18; GE = 12; IE = 6
Step-by-step explanation:
The key to the question is to realize or find out what a centroid is and what it does. You can solve this question by knowing three things.
- The centroid is the meeting point of the three medians ( a median is a line that connects the midpoint of the side opposite a given vertex).
- The centroid divides the median in a ratio of 2:1. The longest segment is from the vertex to the centroid.
- The shortest segment is from the centroid to the midpoint of the side opposite the given vertex.
Point two is what you have to focus on.
GE/EI = 2/1
GE = 12 Given
Solution
GE / EI = 2/1 Substitute for the given
12 / EI = 2/1 Cross multiply
2*EI = 12 * 1 Simplify the right
2 * EI = 12 Divide by 2
EI = 12/2 Divide
Part Two
GI = EI + GE
GI = 6 + 12
GI = 18
EI = 6
Answer:
1) 2 and 6 ; 4 and 8 ; 1 and 5 ; 3 and 7
2) 3 and 6 ; 4 and 5
3) 1 and 8 ; 2 and 7
