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4 years ago

15

) Find the integral of the following distributed loads over the length L, i.e., the total force. Show that it is equal to the ar

ea under the distributed load

1 answer:

serg [7]4 years ago

5 0

Jajahajaiahsvnsjajasnannanananannanakakqkehehsbnanakw

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Morgan is making to cookie recipes recipe a calls for 1/3 less than twice the number of cups of sugar that recipe be calls for i

Kitty [74]

Answer:

(1/3) (2) (number of cups) = 16

(1/3) (2)(n) =16

(2/3) (n) = 16

(2/3)n=16

n=16(3/2)

n=?

Step-by-step explanation:

3 0

3 years ago

Help Will give brainliest!

inn [45]

Answer:

B

• Compute the value of each expression.

• Compare the values. If they are equal, the expressions are equivalent.

Step-by-step explanation:

After you Simplify each expression and Substitute a number for each variable you have to compute it and after you do you have to compare and then you will see if they are equal.

This is my first time doing this so If it is wrong Im sorry.

5 0

3 years ago

Read 2 more answers

Sarah’s dog weighs 3 pounds more than 9 times the weight of Keiko’s dog. What expression could be used to find the weight of Sar

Arlecino [84]

Answer:

9x+3

Step-by-step explanation:

8 0

3 years ago

wildlife protection groups buld bat houses to help sve bate one bat house holds about 300 bats larry says 12 bat houses hold abo

stiv31 [10]

No, I do not agree.

one bat hous holds about 3000 bats => 300 bats / house

So, to estimate the number of bats holded by 12 bat houses do>

300 bat / house * 12 house = 3600 bats

That is very far from the 4500 bats that Larry says.

3 0

3 years ago

A random sample of 130 students is chosen from a population of 4,500 students. The mean IQ in the sample is 120, with a standard

barxatty [35]

Answer:

$120-2.614\frac{5}{\sqrt{130}}=118.85$

$120+2.614\frac{5}{\sqrt{130}}=121.15$

Step-by-step explanation:

Information given

$\bar X= 120$ represent the sample mean

$\mu$ population mean (variable of interest)

s=5 represent the sample standard deviation

n=130 represent the sample size

For this case we can't set a margin of error just with a % since they not specify 1.13% respect to something for this case we can omit this value

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=130-1=129$

The Confidence level is 0.99 or 99%, the significance would be $\alpha=0.01$ and $\alpha/2 =0.005$ , and the critical value would be $t_{\alpha/2}=2.614$

And replacing we got:

$120-2.614\frac{5}{\sqrt{130}}=118.85$

$120+2.614\frac{5}{\sqrt{130}}=121.15$

3 0

3 years ago