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3 years ago

15

) Find the integral of the following distributed loads over the length L, i.e., the total force. Show that it is equal to the ar

ea under the distributed load

1 answer:

serg [7]3 years ago

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3 and 1 half to the power of 2 simplify

Elenna [48]

3 and 1 half is also known as 3.5,
3.5 x 3.5 = 12.25
in fractions that is 12 and 1 quarter

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3 years ago

Read 2 more answers

Simplify by expressing fractional exponents instead of radicals

igomit [66]

Answer:

$a^{\frac{1}{2}}b^{\frac{1}{2}}$

Step-by-step explanation:

Given:

The expression in radical form is given as:

$\sqrt{ab}$

We need to express this in fractional exponent form.

We know that,

$\sqrt a=a^{\frac{1}{2}}$

Also, $\sqrt{ab}=\sqrt a\times \sqrt b$

Now, clubbing both the properties of square root function, we can rewrite the given expression as:

$\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}$

So, the given expression in fractional exponents form is $a^{\frac{1}{2}}b^{\frac{1}{2}}$ .

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3 years ago

A square piece of paper has an area of 36 square inches what is the perimeter of the paper

Gekata [30.6K]

Lets represent the side of the square as s , since we know the area is 36. write s

${s}^{2} = 36$

$s = \sqrt{36}$

the square root of 36 is 6. So, we know the side is 6. The formula for perimeter is P= s+s+s+s , but since it is a square and all the sides are equal, for a perimeter of a square you can do p= 4s , now substitute 6 for s to get 4(6)=24 so the perimeter of a square would be 24 inches

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3 years ago

The Reel Good Cinema is conducting a mathematical study. In its theater, there are 200 seats. Adult tickets cost $12.50 and chil

Vlada [557]

If the goal is to sell at least $1500 worth of tickets then what you can do is add the 12.50+ 6.25 which well equal 18.75. Then you can divide 1500/18.75 which eqauls to 80 meaning at least 80 seats must be sold

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3 years ago

How do you evaluate sin(13π/12)?

Alekssandra [29.7K]

13pi/12 lies between pi and 2pi, which means sin(13pi/12) < 0

Recall the double angle identity,

sin^2(x) = (1 - cos(2x))/2

If we let x = 13pi/12, then

sin(13pi/12) = - sqrt[(1 - cos(13pi/6))/2]

where we took the negative square root because we expect a negative value.

Now, because cosine has a period of 2pi, we have

cos(13pi/6) = cos(2pi + pi/6) = cos(pi/6) = sqrt[3]/2

Then

sin(13pi/12) = - sqrt[(1 - sqrt[3]/2)/2]

sin(13pi/12) = - sqrt[2 - sqrt[3]]/2

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3 years ago