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3 years ago

How do I write this in radical form with steps and the final answer please

Mathematics

1 answer:

alekssr [168]3 years ago

7 0

Answer:

6 * $\sqrt[3]{x}$

Step-by-step explanation:

6 x^1/3

The 1 means inside to the power of 1 and the 3 means to the cubed root

6 * $\sqrt[3]{x}$

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This is what I've done so far but does anyone know what I do next or did I make a mistake

grigory [225]

Remmeber, you can do anything to an equation as long as you do it to both sides

for inequalities, if you multiply or divide both sides by a negive, flip the direction of the inequality sign

pemdas always applies
but also the commutative property and assiociative property

so
2(5y+13)-6<20
add 6 both sides
2(5y+13)<26
divide both sides by 2 (easier that distributing)
5y+13<13
minus 13 both sides
5y<0
y<0 is the solution

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4 years ago

Which property justifies the following equation? 7(6+0+5)= 7(6+5)

velikii [3]

Zero
you can double check though

8 0

3 years ago

I am really confused about this question for math.. any help would be really appreciated:

Elina [12.6K]

$y= (\frac 1 4 )^x$

A reflection about the x axis, about y=0, is the mapping (x',y')=(x,-y) so

$y'= -y = - (\frac 1 4)^{x'}$

A dilation of 2 is the mapping (x'',y'')=(2x', 2y')

$x'=x''/2, y'=y''/2$

$y''/2= - (\frac 1 4)^{x''/2}$

$y'' = - 2((\frac 1 4)^{1/2})^{x''}$

$y''= - 2(\frac 1 2)^{x''}$

We can rewrite that without the primes and combine the powers of 2.

$y = - 2^{1-x}$

Let's graph these and see if we're close,

Plot y= (1/4)^x, y= - (1/4)^{x}, y = - 2^{1-x}

6 0

3 years ago

Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*

dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\$

$5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\$

$\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3$

7 0

3 years ago

Read 2 more answers

What is the slope of the line in the following graph? 1/3 1/2 2 3

ivanzaharov [21]

For every 3 you go across you go up 1 so the gradient is rise/run = 1/3

Therefore gradient is 1/3

5 0

3 years ago

Read 2 more answers