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3 years ago

A rectangle has a height of 4 and a width of x2 + 3x + 2.

Mathematics

1 answer:

otez555 [7]3 years ago

5 0

<h3><u>Given</u>:</h3>

A rectangle has a height of 4 and a width of x² + 3x + 2.

The area of the entire rectangle.

<h3><u>Solution</u>:</h3>

Hence, we know that area of rectangle is equals to the product of length and breadth.

Therefore, the area of rectangle is,

$= 4 \times( {x}^{2} +3x + 2 ) \\ = 4({x}^{2} + 3x + 2) \\ = \green{ \boxed{4 {x}^{2} + 12x + 8}}$

Therefore, the answer is 4x² + 12x + 8.

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2 years ago

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A population has a known standard deviation of 1.27 and a sample space contains 85 values find the margin of error needed to cre

r-ruslan [8.4K]

Answer:

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this question:

$\sigma = 1.27, n = 85$

$M = z*\frac{\sigma}{\sqrt{n}}$

$M = 2.575*\frac{1.27}{\sqrt{85}}$

$M = 0.3547$

The margin of error needed to create a 99% confidence interval estimate of the mean of the population is of 0.3547

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3 years ago

What is the missing angle 78+31+x=180

icang [17]

Answer:

Step-by-step explanation:

78+31=109 so 180-109=71

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2 years ago

Form a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3

polet [3.4K]

The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Step-by-step explanation:

We need to find a polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3.

If -1, 1 and 3 are real zeros, it can be written as:

x= -1, x= 1, and x = 3

or x+1=0, x-1=0 and x-3=0

Finding polynomial by multiply these factors:

$(x+1)(x-1)(x-3)=0\\(x+1)(x(x-3)-1(x-3))=0\\(x+1)(x^2-3x-x+3)=0\\(x+1)(x^2-4x+3)=0\\x(x^2-4x+3)+1(x^2-4x+3)=0\\x^3-4x^2+3x+x^2-4x+3=0\\Combining\,\,like\,\,terms:\\x^3-4x^2+x^2+3x-4x+3=0\\x^3-3x^2-x+3=0$

So, The polynomial function whose real zeros are in -1, 1, 3 and whose degree is 3 is $x^3-3x^2-x+3=0$

Keywords: Real zeros of Polynomials

Learn more about Real zeros of Polynomials at:

#learnwithBrainly

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3 years ago