Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
Answer:
600
Step-by-step explanation:
36 times 18=648 but u need to add o the nearest hundred
Answer:
$36.88
Step-by-step explanation:
4 inch cost $2.95
50 inch cost 2.95*50 / 4 = $36.875 = $36.88
I think -8 but i’m not sure tho