The result of rolling a number cube 7 times is a 7-digit number composed of digits 1,2,3,4,5 and 6 so that digits can repeat. The total number of possibilities is 6^7.
The number of possibilities where 4 appears exactly two times is 5^5*(7!-6!/2).
5^5 is the number of 5-digits numbers composed of digits 1,2,3,5 and 6 so that digits can repeat.
7! is the number of permutations of digits 1,2,3,4,4,5 and 6.
6! is the number of permutations of digits 1,2,3,{4,4},5 and 6.
We don't want to subtract all numbers where digits 4 appear side by side. That's why we must divide 6! by 2.
Finally, the probability is P=5^5(7!-6!/2)/7^7
Answer:
The GCF is -10
Step-by-step explanation:
-10 in the highest/largest number that goes into both -20 and -50.
if you have to factor -20v-50 as well it would be:
-10(2v+5)
and to check if that answer is correct, distribute -10 inside the parenthesses:
-10 times 2v = -20v
-10 times 5 = -50
-20v-50
Five times two times three times fifteen
C is the answer !!!!!!!!!
