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dusya [7]
3 years ago
10

The height, h, of a ball that is tossed into the air is a function of the time, t, it is in the air. The height in feet fort sec

onds is given by the function h(t) = -16t^2 + 96t What is the domain of the function? a) [0,00) b) (-0,co) Oc) (0,co) d) (0,5) e) none
Mathematics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

[0,\infty)

Step-by-step explanation:

We have been given that the height, h, of a ball that is tossed into the air is a function of the time, t, it is in the air. The height in feet fort seconds is given by the function h(t)=-16t^2+96t.

We are told that the height of the ball is function of time, which means time is independent variable.

We know that the domain of a function is all real values of independent variable for which function is defined.

We know that time cannot be negative, therefore, the domain of our given function would be all values of t greater than or equal to 0 that is [0,\infty).

You might be interested in
A pair of shoes is on sale for $66.00. This is 75% of the original price. What was the original price?
sergejj [24]

Answer:

$88.00

Step-by-step explanation:

66=3/4x

66/.75=66*4/3=88

3 0
3 years ago
I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
4 years ago
Can you guys please help me with math? (Pt 2.)
Firlakuza [10]
(0,a)

it didnt move left or right on the x-axis
it went up a units (since its half of 2a)
5 0
3 years ago
Read 2 more answers
Im not sure how to find the missing angle
LuckyWell [14K]

Answer:

Step-by-step explanation:

the question is asking for the length of the side labeled x

use Pythagoras'  theorem to find that side

where c = x   because c represents the hypotenuse in the theorem and x is on the hypotenuse in this problem

c = \sqrt{a^{2} + b^{2} }

sooo  plug in a = 14 and b = 10

c = \sqrt{14^{2} + 10^{2} }

c = \sqrt{196+100}

c = \sqrt{296}

c= 17.20465.....  ( that's the approx. length of side x in the problem )

since this is a right triangle we could use trigonometry to find the two angles use SOH CAH TOA  to remember how those functions fit on the triangle.

Sin(Ф)=Opp/Hyp  Cos(Ф)=Adj/Hyp  Tan(Ф)=Opp/Adj

since we know the Hyp (hypotenuse) and the side adjacent will be the side with the 10 soooo...

Cos(Ф)=10/17.20465

Ф = arcCos(10/17.20465)

Ф = 54.4623°  is the angle on the side with 10

the side with 14 then has an angle of 35.5376°

:)

5 0
3 years ago
The question is below answer please
liraira [26]
1. 51
2. 10
3. 14
4. 7
5. 13
6. 6
7. 4
8. 22
9. 29
10. 36
You just have to cross multiply and then divide it by 100
7 0
4 years ago
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