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matrenka [14]
2 years ago
14

Can someone please help me with #1?

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
7 0

Answer: 4x, 2x+2x, x+x+x+x

Step-by-step explanation: all are the same expresions.

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Can someone plz answer this correctly and quickly.
rosijanka [135]
V = \pi \pir^{2}h

1. Find the radius. 

8/2 = 4

2. Square the radius.

4^{2} = 16

3. Multiply that by pi.

3.14 * 16 = 50.24

4. Multiply that by the height.

50.24 * 20 = 1004.8

5. Now find 60% of that.

1004.8 * 0.6 = 602.88

V = 602.88 m^{3}

Honestly, it's been a while since I've done this, but I believe this is the answer.
7 0
3 years ago
Joe barrowed $2,000 from the bank at a rate of 7% simple interest per year. How much will be in your account in 5 years?
timofeeve [1]
For the answer to the question above,
The simple interest formula is I = P * r * t

P is the principal (2,000)
r is the interest rate (7% or 0.07)
t is the time (5)

2000 * 0.07 * 5 = 700

$700.00 is the interest

Joe has to pay $700.00 in interest.
I hope this helps
4 0
2 years ago
A polynomial function upper P left parenthesis x right parenthesis with rational coefficients has the given roots. Find two addi
mylen [45]

Given that a polynomial function P(x) has rational coefficients.

Two roots are already given which are i and 7+8i,

Now we have to find two additional roots of P(x)=0

Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.

conjugate of a+bi is given by a-bi

So using that logic, conjugate of i is i

also conjugate of 7+8i is 7-8i

Hence final answer for the remaining roots are (-i) and (7-8i).

5 0
2 years ago
What is an equation of the line that passes through the points (0, -1)(0,−1) and (6, 1)(6,1)?
horrorfan [7]

slope = y2 - y1 \div x2 - x1

1 -  - 1 \div 6 - 0

2 \div 6

1 \div 3

y = mx + c

1 = 1 \div 3 \times 6 + c

1 = 2 + c

c = 3

y = 1 \div 3x + 3

5 0
3 years ago
Write the trinomial as a square of a binomial<br> x^2+2xy+y^2
vitfil [10]

Answer:

\large\boxed{x^2+2xy+y^2=(x+y)^2}

Step-by-step explanation:

(x+y)^2=(x+y)(x+y)\\\\\text{Use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(x)(x)+(x)(y)+(y)(x)+(y)(y)=x^2+xy+xy+y^2=x^2+2xy+y^2

3 0
3 years ago
Read 2 more answers
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