Number 1 is C.
Number 2 is C.
Did you need all of them?
Solution:
y = 2x^2 - 3 ---- equation 1
y = 3x - 1 ------equation 2
Then we get,
2x^2 - 3 = 3x - 1
Now, simplifying the equation, we get
2x^2 - 3x - 3 + 1 = 0
2x^2 - 3x - 2 = 0
After factoring the equation, we get
(2x+1)(x-2) = 0
So, this means
(2x+1) = 0 and (x-2) = 0
From this, we get
x = -1/2 and x = 2
Putting values of x = -1/2 in equation 2
y = 3(-1/2) - 1
y = -2.5
Now, putting value of x = 2 in equation 2
y = 3(2) -1
y = 5
Answer:
D) 40
Step-by-step explanation:
First, identify what you know:
1) Michael is directed to pick a number between 1 and 50
2) Michael picks a number that is less than 50
3) The number chosen, is a multiple of 5 and 8
A multiple is a number that can be divided by another number without a remainder. What number can be divided by 5 and 8 without having a remainder?
40/5 = 8
40/8 = 5
Michael chose 40!!
D, E and F will lie on the line
Answer:
x=-1 y=2
Step-by-step explanation:
Use Elimination or Substitution (Elimination shown below)
6x+5y=4
6x-7y =-20 <- Multiply by -1
-6x+7y=20
12y = 24
y=2
Plug back into either of the equations and solve for x.
6x + 10= 4
6x = -6
x = -1
Double check work:
-6+10 = 4
