Answer:
a+b = 12
Step-by-step explanation:
There are 36 possible outcomes for rolling two dice. Let A be the number rolled by Abed and D be the number rolled by Dawn. The sample space, in the format [A,D], of all of the possibilities in which Dawn's number is larger is:
[5,6]
[4,5] [4,6]
[3.4] [3,5] [3.6]
[2,3] [2.4] [2,5] [2.6]
[1,2] [1,3] [1.4] [1,5] [1.6]
There are 15 ways out of 36 possible ways of Dawn getting the higher number. In the simplest form:
Answer:
C
Step-by-step explanation:
The function multiplies by 8 so 6 would be 48 and 10 would be 80.
Have a great day!
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
Answer:
This function is an even-degree polynomial, so the ends go off in the same directions, just like every quadratic I've ever graphed. Since the leading coefficient of this even-degree polynomial is positive, the ends came in and left out the top of the picture, just like every positive quadratic you've ever graphed. All even-degree polynomials behave, on their ends, like quadratics.
Step-by-step explanation:
