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3 years ago

Given the triangles are similar, calculate the value of y to the nearest tenth.

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

y=4.5

This is because the ratio between the two triangles is 1:2 so the side lengths of the first triangle is half the corresponding side length of the second triangle.

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Chloe has been offered a new job in the women’s shoe department at Macy’s. She has two salary options. She can receive a salary

gladu [14]

Answer:

depends on x

Step-by-step explanation:

if x is equal or more than $3150 option 2 is the answer

7 0

3 years ago

What is it a ,b,c,or D can I get a step by step explanation

ANEK [815]

The answers are b and c. Plug in -4 for x and solve each option

2(-4) -8 = 0. 0 does not equal 1
3(-4) +8 = -4
1/2 * -4 + 3 = 1, -4+5 = 1
2(1- -4) = 10, -4 + 2 = -2

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4 years ago

The hockey team won 60 out of the 80 games it played this year. What percent of the games did the team win?

irina1246 [14]

Answer is in the file below

tinyurl.com/wtjfavyw

8 0

3 years ago

Read 2 more answers

Enter the range of values for x

Pavlova-9 [17]

<em>Greetings from Brasil...</em>

See the attached figure. The smaller the θ angle, the smaller the AB side will be. If the angle θ = 90º, then AB = 25. As θ < 90, then AB < 25

5X - 10 < 25

5X < 25 + 10

X < 35/5

X < 7

The AB side can be neither zero nor negative. So

5X - 10 > 0

5X > 10

X > 10/5

X > 2

8 0

4 years ago

Can someone help me with this question? You don’t really have to tell me the answer but just how to solve it.

Veronika [31]

part A

if the paperbacks are 40% less, that means 100% - 40% = 60%, they actually are 60% of the price of the hardcover ones.

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{60\% of 24.99}}{\left( \cfrac{60}{100} \right)249.99}\implies 14.994$

part B

so, if they return it, they get 1/3 credit, if they try to sell it, is half off, which is more than 1/3. 22 got damaged.

$\bf \stackrel{\textit{damaged books at half-price}}{(22\cdot 14.994)\cfrac{1}{2}\implies 164.934}~\hfill \stackrel{\textit{damaged books at one-third price}}{(22\cdot 14.994)\cfrac{1}{3}\implies 109.956} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 164.934 - 109.956 = 54.978~\hfill$

part C

$\bf \textit{First Day}~\hfill \stackrel{hardcover}{3(24.99)}+\stackrel{paperback}{8(14.994)}+\stackrel{damaged}{3\left( 14.994\cdot \frac{1}{2} \right)} \implies 217.413 \\\\\\ \textit{Second Day}~\hfill \stackrel{hardcover}{4(24.99)}+\stackrel{paperback}{5(14.994)}+\stackrel{damaged}{8\left( 14.994\cdot \frac{1}{2} \right)}\implies 234.906 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \boxed{17.493}$

I don't think she is incorrect, $17.5 is close to $20, she didn't say it was exactly $20, just thereabouts, and 17.5 is around that much.

8 0

3 years ago