Answer:
You want to make it so you have an even amount of both, correct? This is where you need to know your multiples... here is what I got...
Step-by-step explanation:
By 4 packs of hotdogs and 5 packs of hotdog buns, this way you end up with 40 of each.
Answer:
![\hat p = \frac{Lower+Upper}{2}](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%20%5Cfrac%7BLower%2BUpper%7D%7B2%7D)
And replacing the info from the problem we have:
![\hat p = \frac{0.018+0.046}{2}= 0.032](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%20%5Cfrac%7B0.018%2B0.046%7D%7B2%7D%3D%200.032)
So then the best estimator for the true proportion p is given by
or equivalent to 3.2 %
Step-by-step explanation:
We want to find a confidence interval for a proportion p who represent the parameter of interest.
The confidence interval would be given by this formula:
![\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=%5Chat%20p%20%5Cpm%20z_%7B%5Calpha%2F2%7D%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
For this case the 90% confidence interval is given by (1.8%=0.018, 4.6%=0.046) after apply the last formula
Since the confidence interval is symmetrical we can estimate the point estimator of the true percentage with this formula:
![\hat p = \frac{Lower+Upper}{2}](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%20%5Cfrac%7BLower%2BUpper%7D%7B2%7D)
And replacing the info from the problem we have:
![\hat p = \frac{0.018+0.046}{2}= 0.032](https://tex.z-dn.net/?f=%5Chat%20p%20%3D%20%5Cfrac%7B0.018%2B0.046%7D%7B2%7D%3D%200.032)
So then the best estimator for the true proportion p is given by
or equivalent to 3.2 %
Answer:
Step-by-step explanation:
If the width is 9x², then the length is 27x^5+9x^4-18x^3/9x², which equals 3x³+x²+2x. ☺☺☺☺
Answer: 6
Step-by-step explanation:
2/3 of 9 is basically 2/3 times 9