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Art [367]
3 years ago
14

Help ASAP!!!!! ;))) tyyy

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0
3. dude these are easy. I think you got it.
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During each minute of a comedy show, Carlin laughs 5 times. Carlin watches 3 comedy shows every day, and each show is 40 minutes
Salsk061 [2.6K]
5 x 40 = 200
200 x 3 = 600

Carin laughs 600 times every day due to the comedy shows.
(That is a hell lot of laughing in one day... )
;)
3 0
3 years ago
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How Manu grams of oat flour does Mr.Price need to use? complete the table​
allochka39001 [22]

Answer:

225

Step-by-step explanation:

Because of 45 time 5

8 0
3 years ago
Given the system of equations, what is the x-coordinate of the solution?
Nimfa-mama [501]
Answer: Choice C) -11

-----------------------------------

Explanation:

The first equation given is y = 3 - 1/2x
In other words, y is the same as 3 - 1/2x. 
We can replace y in the second equation with 3 - 1/2x
This is known as substitution (think of a substitute teacher who is a temporary replacement for your teacher)

Doing this leads to...
3x+4y = 1
3x+4*y = 1
3x+4*( y ) = 1
3x+4*( 3 - 1/2x ) = 1 <<--- y has been replaced with 3-1/2x
3x+4*(3) +4*(-1/2x) = 1
3x+12-2x = 1
3x-2x+12 = 1
x+12 = 1
x+12-12 = 1-12 <<-- subtracting 12 from both sides
x = -11
Which is why the answer is choice C) -11
6 0
3 years ago
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Maya thinks there are twice as many players in the league with more than 4 years of experience than there are players with less
iragen [17]
Sorry don’t now the answer to this problem
6 0
3 years ago
If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?
Fantom [35]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

v=\frac{d}{t}

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

d_1 = v_1 t_1 = (7)(0.4)=2.8 mi

Then the distance covered in the second part is d_2, so the total distance is

d=2.8+d_2 (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

t=0.4+0.8=1.2 h

So we can write the average speed as

v=\frac{2.8+d_2}{1.2} (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi

And therefore, the speed in the second part must be

v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph

4 0
3 years ago
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