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disa [49]
3 years ago
14

What is 2x566!!!!!!!!!!!

Mathematics
2 answers:
Effectus [21]3 years ago
8 0
That would be 1,132





Please mark me brainliest.
madreJ [45]3 years ago
5 0
2 * 566 = 1132

Hope I helped!

Let me know if you need anything else!

~ Zoe
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Does the following set of coordinates represent a function? *
serg [7]

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no because the x value -2 has two corasponding y values

Step-by-step explanation:

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2 years ago
The following sequence is an arithmetic sequence. [-9, -2, 5, 12,...]
egoroff_w [7]

Answer: The common difference is 7, and the next two terms are 19 and 26.

Step-by-step explanation:

Between -9 and -2 there is +7, same with between -2 and 5, as well as 5 and 12. Adding 7 to 12 again gets 19, and adding 7 to 19 gets 26 as well for the next two terms.

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2 years ago
What is the product of 26 and -8.23? Do not round your answer.
Gnesinka [82]

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-213.98

Step-by-step explanation:

4 0
3 years ago
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How do you solve this problem?
larisa86 [58]

Answer:

21

Step-by-step explanation:

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8 0
3 years ago
What is the area of a triangle whose vertices are (4,0), (2,
yan [13]

Answer:

The correct option is;

b) 0 sq, units

Step-by-step explanation:

The vertices of the triangle are;

(4, 0), (2, 3), (8, -6)

The distance formula fr finding the length of a segment is given as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where, (x₁, y₁) and (x₂, y₂) are the coordinates of the end points of the line

For the points (4, 0) and (2, 3) , we have;

√((3 - 0)² + (2 -4)²) = √13

Distance from (4, 0) to (2, 3) = √13

For the points (4, 0) and (8, -6) , we have;

√((-6 - 0)² + (8 -4)²) = √13 =

Distance from (4, 0) to (8, -6) = 2·√13

For the points (2, 3) and (8, -6) , we have;

√((-6 - 3)² + (8 -2)²) = 3·√13 =

Distance from (2, 3) to (8, -6) = 3·√13

Therefore, the perimeter of the triangle = 6·√13

The semi perimeter s = 3·√13

The area of the triangle,  A  = \sqrt{s\cdot \left (s-a  \right )\cdot \left (s-b  \right ) \cdot \left ( s-c  \right )}

Where;

a, b, and c are the length of the sides of the triangle;

A  = \sqrt{3\cdot \sqrt{3} \cdot \left (3\cdot \sqrt{3} -\sqrt{3}   \right )\cdot \left (3\cdot \sqrt{3} -2 \cdot \sqrt{3}   \right ) \cdot \left ( 3\cdot \sqrt{3} -3\cdot \sqrt{3}   \right )} = 0

Therefore, the area = 0 sq, units.

6 0
3 years ago
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