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olganol [36]
4 years ago
5

Which formula can be used to describe the sequence? -3, 3/5,-3/25,3/125,-3/625​

Mathematics
1 answer:
givi [52]4 years ago
5 0

Answer:

i have the same question on my sheet

Step-by-step explanation:i need help with that one too

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Find the LCM of the following
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Answer:

A. LCM of 6,9, and 15 is 90.

B. LCM of 3,12, and 16 is 48.

C. LCM of 8,9, and 12 is 72.

D. LCM of 24 and 18 is 72.

E. LCM of 21 and 28 is 84.

F. LCM of 19 and 42 is 798.

Step-by-step explanation:

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3 years ago
Help! Exponential Equation WITHOUT CALCULATOR
ale4655 [162]

1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

\\ \\ 2.( 2^{x})^{3} - (2^{-x}^) ^{3}= (2^{x} -2^{-x})(2^{2x}+2^{x}*2^{-x}+2^{-2x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+2^{x}*2^{-x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+1)
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})((2^{2x}+2^{-2x})+1)


\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
\\ \\ 2^{3x}-2^{-3x} =76

4 0
3 years ago
How do you write 4.8 repeating as a fraction
gulaghasi [49]
24/5
I think this is the right answer, hope this help
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3 years ago
Help I need to tune in all my late work ...
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Should be a scale factor of y= 1/9
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Suppose you buy a phone for $200 and its value depreciates linearly. If the phone is worth $115 after four years, then what is t
vredina [299]

Answer:

$72.5

Step-by-step explanation:

  • Initial value = $200
  • Depreciated value after 4 years = $115

<u>Since depreciation rate is linear, then:</u>

  • 200 - 4x = 115
  • 4x = 200 - 115
  • 4x = 85
  • x = 85/4
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<u>Value after 6 years:</u>

  • 200 - 6*21.25 = 200 - 127.5 = $72.5
3 0
3 years ago
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