Answer: 1. the negative of the conclusion is true
If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
The discriminant can be found using the formula b^2-4ac
First put your equation in standard form, where all your values are on one side, and just add f(x) or y in front of your equation.
y= 8p^2-8p+2
The first value of your equation is a (a=8)
The second term of your equation is b (b=-8)
The last term of your equation is c (c=2)
Plug in the values to the discriminant equation b^2-4ac
Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:




