Answer:
A (2,-2.5)
Step-by-step explanation:
Is 2 units right and 2.5 units down, right where point C is.
Answer:
a.) one sample t test
b.) H0 : μ = 59.3
c.) H1 : μ > 59.3
d.) μ = 59.3 ; σ = 39.84
e.) xbar = 79.4 ; s = 61.36
Test statistic = 3.16
Step-by-step explanation:
Given the sample data:
49.00 49.00 49.00 49.00 49.00 63.00 63.00 63.00 63.00 63.00 199.00 199.00 199.00 199.00 199.00 38.00 38.00 38.00 38.00 38.00 48.00 48.00 48.00 48.00 48.00 49.00 63.00 199.00 38.00 48.00
Sample size, n = 30
Using calculator :
xbar from the data above = 79.4
Standard deviation = 61.359
H0 : μ = 59.3
H1 : μ > 59.3
Test statistic :
(Xbar - μ) ÷ (σ/sqrt(n)
σ = 34.83
(79.4 - 59.3) ÷ (34.83/sqrt(30))
20.1 ÷ 6.359
Test statistic = 3.16
Answer:
y=4
Step-by-step explanation:
3 x 2=6
6 - 2= 4
15 x 7 days = 105 then multiply 5 weeks. 5 x 105 = 525 miles
Answer:
Part 1 .
As per the given statement: In t hours the train has traveled s miles.
Distance of the train = s mile
Time = t hours
Formula for :
Speed of the train(v) = 
or
mph .....[1]
Substitute the value of t = 3 hours and s = 180 miles in [1], to solve for v;

Therefore, the speed of the train(v) is, 60 mph
Part 2.
Similarly,
The formula for speed of the train (v) is given by;

Substitute the value of t = 2.5 hours and s = 225 miles to solve for v;

Therefore, the speed of the train(v) is, 90 mph