Standard form is ax+by=c
normally a is positive and a and b are integres
y=mx+b
m=slope
b=yint
y=1/2x+3
minus 1/2 x both sides
-1/2x+y=3
times -2
x-2y=-6
<span><span><span>9/10 - 7/20=(9x20) - (7x10)= 10x20= 110/200 110 divided by 10/ 200 divided by 10= 11/20. So that brings you to your answer of 11/20. hope this helps :)
</span></span></span>
To solve for the missing steps, let's rewrite first the problem.
Given:
In a plane, line m is perpendicular to line t or m⟂t
line n is perpendicular to line t or n⟂t
Required:
Prove that line m and n are parallel lines
Solution:
We know that line t is the transversal of the lines m and n.
With reference to the figure above,
∠ 2 and ∠ 6 are right angles by definition of <u>perpendicular lines</u>. This states that if two lines are perpendicular with each other, they intersect at right angles.
So ∠ 2 ≅ ∠ 6. Since <u>corresponding</u> angles are congruent.
Therefore, line m and line n are parallel lines.
<span>
<em>ANSWERS: perpendicular lines, corresponding</em>
</span>
48 + 24 + 12 + 6 = 90 inches or <span>3*(16+8+4+2) = 90 will be the right answer.</span>
A secure line of credit is one in which the borrower uses an asset as collateral to secure a loan.