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abruzzese [7]
3 years ago
5

The quotient of four times a number and nine in an algebraic expression

Mathematics
1 answer:
amid [387]3 years ago
3 0

Answer:

4x/9

Step-by-step explanation:

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Finish solving the system of equations –9.5x – 2.5y = –4.3 and 7x + 2.5y = 0.8 using the linear combination method
jek_recluse [69]
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5 0
3 years ago
Alice's garden produced 17 yellow tomatoes this year. She also grew 18 roma
Sever21 [200]

Answer:

C

Step-by-step explanation:

You add both types of tomatoes together to get the total amount of tomatoes

4 0
3 years ago
I need help with this please
Lelechka [254]

There are 36 possible combinations that can occur when 2 dice are rolled. For the sake of this question, we'll count instances where dice 1 = 3/dice 2 = 2 and dice 1 = 2/dice 2 = 3.

Now, let's think about all of the possible ways a total of 5 could be rolled.

1 + 4

2 + 3

3 + 2

4 + 1

That's 4 possibilities to roll a total of 5 out of 36 possible outcomes.

4 / 36 = ? / 180

---Now, we need to use a proportion in order to figure out the possibilities out of 180.

36x = 720

x = 20

If you rolled a pair of fair dice 180 times, you would expect to roll a total of 5, 20 times.

Hope this helps!

4 0
2 years ago
(1/3) a = -5 What does a equal?????????????????????????????????????????????????????
KiRa [710]

Answer:

minus 15

Step-by-step explanation:

times the bottom by the right hand side

6 0
2 years ago
Consider an experiment where two 6-sided dice are rolled. We can describe the ordered sample space as below where the first coor
agasfer [191]

Answer:

  • E = { (4,1) , (3,2) , (2,3) , (1,4) }
  • P(E)=\frac{1}{9}
  • P(F|E)=\frac{1}{4}

Step-by-step explanation:

Let's start writing the sample space for this experiment :

S= { (1,1) , (1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,1) , (2,2) , (2,3) , (2,4) , (2,5) , (2,6) , (3,1) , (3,2) , (3,3) , (3,4) , (3,5) , (3,6) , (4,1) , (4,2) , (4,3) , (4,4) , (4,5) , (4,6) , (5,1) , (5,2) , (5,3) , (5,4) , (5,5) , (5,6) , (6,1) , (6,2) , (6,3) , (6,4) , (6,5) , (6,6) }

Let's also define the event E ⇒

E : '' The sum of the two dice is 5 ''

We can describe the event by listing all the favorables cases from S ⇒

E = { (4,1) , (3,2) , (2,3) , (1,4) }

In order to calculate P(E) we are going to divide all the cases favorables to E over the total cases from S. We can do this because all 36 of these possible outcomes from S are equally likely. ⇒

P(E)=\frac{4}{36}=\frac{1}{9} ⇒

P(E)=\frac{1}{9}

Finally we are going to define the event F ⇒

F : '' The number of the first die is exactly 1 more than the number on the second die ''

⇒

F = { (2,1) , (3,2) , (4,3) , (5,4) , (6,5) }

Now given two events A and B ⇒

P ( A ∩ B ) = P(A,B)

We define the conditional probability as

P(A|B)=\frac{P(A,B)}{P(B)} with P(B)>0

We need to find P(F|E) therefore we can apply the conditional probability equation :

P(F|E)=\frac{P(F,E)}{P(E)}   (I)

We calculate P(E)=\frac{1}{9} at the beginning of the question. We only need P(F,E).

Looking at the sets E and F we find that (3,2) is the unique result which is in both sets. Therefore is 1 result over the 36 possible results. ⇒

P(F,E)=\frac{1}{36}

Replacing both probabilities calculated in (I) :

P(F|E)=\frac{P(F,E)}{P(E)}=\frac{\frac{1}{36}}{\frac{1}{9}}=\frac{1}{4}=0.25

We find out that P(F|E)=\frac{1}{4}=0.25

6 0
3 years ago
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