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mel-nik [20]
3 years ago
11

How do i solve x squared = 4x -5

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

x = 2 ±i

Step-by-step explanation:

x^2 = 4x-5

Subtract 4x from each side

x^2 - 4x = 4x-5 -4x

x^2 - 4x= -5

Complete the square

Take the coefficient of the x term, divide by 2 and square it

-4/2 =2   2^2 =4

Add 4 to each side

x^2 -4x+4 = -5 +4

The left side is (x-coefficient of the x term/2)^2

(x-2)^2 = -1

Take the square root of each side

sqrt((x-2)^2) = sqrt(-1)

x-2 = ±i

Add 2 to each side

x-2+2 = 2 ±i

x = 2 ±i

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Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
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Ksivusya [100]
<span>The best way to solve each equation is:
 
</span> 1) 5x2 + 12x - 3 = 0 -----> solve by quadratic formula 
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8 0
3 years ago
2. Decide which estimate is closest to the actual answer. Explain your reasoning.
sashaice [31]
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Question C
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A man bought 250 electric lanterns in the united States of America for $5000. he sold them them in lagos at 1,920 naira each. at
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Answer: 4166.67$

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1920 x 250 = amount

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1920 x 250= 120%

Cost price = 100%

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1920 x 250 x 100/120 = price

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Exchange rate then was 80 to 1$

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