Answer: Although A and AT have the same eigenvalues, they may actually have different eigenvectors for that particular eigenvalue. Therefore A and AT have at least one eigenvector that aren't in common.
Step-by-step explanation:
These two attachment explains the provings and counterexamples briefly and simply
Use distrubutive property <em>a(b + c) = ab + ac</em>
6(5r - 4) - 2(r - 7s - 3)
= (6)(5r) + (6)(-4) + (-2)(r) + (-2)(-7s) + (-2)(-3)
= 30r - 24 - 2r + 14s + 6
= (30r - 2r) + 14s + (-24 + 6)
<h3>= 28r + 14s - 18</h3>
Answer:
向きを変えずに形状をスライドさせますか？
Step-by-step explanation:
this translation will not change its orientation
Answer:
A
Step-by-step explanation:
throat bababy
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