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pochemuha
3 years ago
8

Point A(4, 2) is translated according to the rule (x, y) -> (x + 1, y – 5) and then reflected across the y-axis. a) In which

quadrant of the coordinate plane is point A located? b) what are the coordinates of translated point A'? in which quadrant of the coordinate plane is point A located? c) what are the coordinates of reflected point A''? in in which quadrant of the coordinate plane is point A located?

Mathematics
1 answer:
Rzqust [24]3 years ago
7 0
<span>a) In which quadrant of the coordinate plane is point A located? Quadrant I

b) what are the coordinates of translated point A'? in which quadrant of the coordinate plane is point A located? (5,-3) ; Quadrant IV

c) what are the coordinates of reflected point A''? in in which quadrant of the coordinate plane is point A located? (-5,-3) ; Quadrant III

Pls. see attachment. </span>

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Answer:

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A necklace has and matching bracelet have two types of beads. The necklace has 12 large beads and 8 small beads and weighs 88 gr
miv72 [106K]

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Step-by-step explanation:

Let,

Weight of one large bead = x

Weight of one small bead = y

According to given statement;

12x+8y=88     Eqn 1

5x+2y=25      Eqn 2

Multiplying Eqn 2 by 4

4(5x+2y=25)\\20x+8y=100\ \ \ Eqn\ 3\\

Subtracting Eqn 1 from Eqn 3

(20x+8y)-(12x+8y)=100-88\\20x+8y-12x-8y=12\\8x=12

Dividing both sides by 8

\frac{8x}{8}=\frac{12}{8}\\x=1.5

Putting x=1.5 in Eqn 1

12(1.5)+8y=88\\18+8y=88\\8y=88-18\\8y=70

Dividing both sides by 8

\frac{8y}{8}=\frac{70}{8}\\y=8.75

Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/11334714
  • brainly.com/question/11345547

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