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2 years ago

13

Angles T and V are complementary. Angle T has a measure of (2x+10) degrees. Angle V has a measure of 48 degrees. What is the val

ue of x?
answer choices
16 degrees

19 degrees

26 degrees

42 degrees

1 answer:

stiks02 [169]2 years ago

5 0

It is 19 degrees (19 times 2 equals 38. 38+10=48

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Asnwer question in screenshot pls

AlexFokin [52]

<h3>Answers:</h3>

first box = 0
second box = 0
third box = 4
fourth box = -3

It's not a typo that 0 is written twice.

==============================================================

Explanation:

This is considered a step function because it resembles steps or a staircase. The vertical pieces aren't drawn to allow it to remain a function (or else it fails the vertical line test). Also there should be open holes at each left endpoint.

Recall that any horizontal line has a slope of 0 due to the fact that the rise is 0

slope = rise/run

The rise takes care of the vertical change in position. But if the line doesn't go up or down, then rise = 0 leads to slope = 0.

In short, the slope of each horizontal portion is 0. It doesn't matter which sub-section you focus on.

This is why you'll type 0 into the first two boxes.

------------------

As for the remaining two boxes, you'll be looking where the graph is the highest and the lowest to determine the max and min y values respectively.

We see that y peaks at y = 4 at the very top. So you'll type 4 into the third box.

Furthermore, we see that the lowest part of the graph is when y = -3. Therefore, this is the minimum aka smallest y value and you'll type -3 into the fourth box.

7 0

2 years ago

Question 12(Multiple Choice Worth 5 points)

34kurt

Answer:

the correct answer is C x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of 12 multiplied by y to the power of negative 12.

hope it helps!

6 0

3 years ago

At what points on the given curve x = 4t3, y = 3 + 40t − 2t2 does the tangent line have slope 1?

dexar [7]

ANSWER

The points are:

(32,-85)

and

$( \frac{500}{27} , \frac{577}{9} )$

EXPLANATION

The given parametric equation that defines the curve is:

$x = 4 {t}^{3}$

$y = 3 + 40t - 2 {t}^{2}$

We differentiate to get,

$\frac{dx}{dt} = 12 {t}^{2}$

$\frac{dy}{dt} = 40 - 4t$

The slope of the tangent is given by;

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{12 {t}^{2} }{40 - 4t}$

For the slope to be 1, then we must solve the following equation for t.

$\frac{12 {t}^{2} }{40 - 4t} = 1$

$12 {t}^{2} = 40 - 4t$

$12 {t}^{2} + 4t - 4 0 = 0$

$3{t}^{2} + t - 10 = 0$

$(t + 2)(3t - 5) = 0$

$t = - 2 \: \: or \: \: t = \frac{5}{3}$

When t=-2, we put -2 into the expression for x and y to get

x=4(-2)³ and y=3+40(-2)-2(-2)²

This implies that,

x=32, y=-85

Hence one point is (32,-85)

Similarly, when

$t = \frac{5}{3}$

$x = \frac{500}{27} ,y = \frac{577}{9}$

Another point is

$( \frac{500}{27} , \frac{577}{9} )$

7 0

3 years ago

a certain stock started the day at $35 a share. By the end of the day the stock had increased by 20%.what is the new price of th

Wittaler [7]

Answer:

New price of the stock = $42

Step-by-step explanation:

Given

Price of stock at the start of the day = $35

Increased by 20% by the end of the day.

To find the new price of the stock which is the price of the stock at the end of the day.

Solution:

Price at start =$35

Increase Percent at the end = 20%

Amount of increase in price = $Increase\ percent \times start\ price = 20\% \times 35 =0.2\times 35=\$7.0$

∴ New price at the end of the day = $Start\ price + increase\ in\ price= \$35+\$7=\$42$

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3 years ago

Trish is taking care of the hans family dogs. The hans leave 7 cans of dog food for the 3 days theyll be away . How many more ca

myrzilka [38]

If the Hans leave for 3 days, and Tish wants to feed the dogs 3 cans each day, we can solve this problem using simple multiplication.

3 days * 3 cans / 1 day = 9 cans

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3 years ago