∛a² → C
From the ' law of exponents '
= ![\sqrt[n]{a^{m} }](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D)
Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
he dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∠x + 90° = 180°
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
1. Arc KL = 23
2. Arc LON = 203
3. Arc OM = 113
4. Arc KNL = 180
5. 157
hope this helps !
The answer is <span>A)(13, 8).
Distance I to F is: yf - yi = -1 - (-4) = -1 + 4 = 3
Distance D to A is: ya - yd = 8 - 2 = 6
</span>Distance D to A : Distance I to F = 6 : 3<span>
6 : 3 = 2, so scale factor is 2.
Among all choices, we see that the y point of another corner is 8, so we need to find x point.
Distance I to H is: xh - xi = -2 - (-7) = -2 + 7 = 5
Distance A to x corner is: x - xa = x - 3
Since </span>Distance I to H is 5, and scale factor is 2, we have:
Distance A to x corner : Distance I to H = 2
Distance A to x corner = 2 * Distance I to H = 2 * 5 = 10
Distance A to x corner is: xa - x = x - 3 = 10
x - 3 = 10
x = 10 + 3
x = 13
