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3 years ago

What the second step in sketching the graph of a rational fintion

Mathematics

1 answer:

lakkis [162]3 years ago

6 0

Putting the dot points is the second

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PLS HELP ME ASAP WILL MARK AS BRAINLIEST!!!

Lesechka [4]

Answer:

5/9=-0.5

-41/90=-0.45

2 7/9=2.7

2 34/99=2.34

-17/30=-0.56

58/99=0.58

Step-by-step explanation:

3 0

4 years ago

What is eight over nine divided by two over three equal to?

Rom4ik [11]

Answer:

4/3

Step-by-step explanation:

Let the fractions be A and B.

Given the following data;

Fraction A = 8/9

Fraction B = 2/3

$\frac {Fraction A}{Fraction B} = \frac {\frac {8}{9}} {\frac {2}{3}}$

$\frac {Fraction A}{Fraction B} = \frac {8}{9} * \frac {3}{2}$

$\frac {Fraction A}{Fraction B} = \frac {24}{18}$

Dividing by 6, we have;

$\frac {Fraction A}{Fraction B} = 4/3$

3 0

3 years ago

What is the reasoning for this proof?

Lorico [155]

Answer:

Mathematical reasoning and proof offer powerful ways of developing and expressing insights about a wide range of phenomena. ... Ultimately, a mathematical proof is a formal way of expressing particular kinds of reasoning and justification. Being able to reason is essential to understanding mathematics.

6 0

4 years ago

Find (f ∘ g)(-6) when f(x) = 9x + 2 and g(x) = -9x2 - 2x + 1.

Salsk061 [2.6K]

Given that the two functions are $f(x)=9x+2$ and $g(x)=-9x^2-2x+1$

We need to determine the value of $(f \circ g)(-6)$

The value of $(f \circ g)(x)$ :

The value of $(f \circ g)(x)$ can be determined using the formula,

$(f \circ g)(x)=f[g(x)]$

Substituting $g(x)=-9x^2-2x+1$ in the above formula, we get;

$(f \circ g)(x)=f[-9x^2-2x+1]$

Now, substituting $x=-9 x^{2}-2 x+1$ in the function $f(x)=9x+2$ , we get;

$(f \circ g)(x)=9(-9x^2-2x+1)+2$

$(f \circ g)(x)=-81x^2-18x+9+2$

$(f \circ g)(x)=-81x^2-18x+11$

Thus, the value of $(f \circ g)(x)$ is $(f \circ g)(x)=-81x^2-18x+11$

The value of $(f \circ g)(-6)$ :

The value of $(f \circ g)(-6)$ can be determined by substituting x = -6 in the function $(f \circ g)(x)=-81x^2-18x+11$

Thus, we have;

$(f \circ g)(-6)=-81(-6)^2-18(-6)+11$

$(f \circ g)(-6)=-81(36)-18(-6)+11$

$(f \circ g)(-6)=-2916+108+11$

$(f \circ g)(-6)=-2797$

Thus, the value of $(f \circ g)(-6)$ is -2797

Hence, Option B is the correct answer.

8 0

4 years ago

WILL MARK BRANIEST: If the magnitude of the block's acceleration is 1.5 m/s2, what is the mass of the block? Show your work. (Th

puteri [66]

Answer:Answer:

F = 0.84 [N]

Explanation:

In order to solve this problem we must take into account Newton's second law, which tells us that the sum of all forces applied on a body must be equal to the product of the mass of the body by its acceleration.

F = m*a

where:

F = force [N]

a = acceleration = 1.4[m/s^2]

m = mass = 0.6 [kg]

F = 0.6*1.4

F = 0.84 [N]

8 0

3 years ago