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Savatey [412]
3 years ago
8

Find the slope from the graph

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0

rise/run 1/4 so it can be

levacccp [35]3 years ago
8 0

Answer:1/4

Step-by-step explanation:

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Write an expression equivalent to b^10/b^5 in the form b^m.
Mars2501 [29]
B^5 when you’re dividing exponents, just subtract!
4 0
3 years ago
Please help me :)) algebra 2! what are the real roots?
irina1246 [14]

Answer:

A

Step-by-step explanation:

So we have the equation:

3(x-4)^\frac{4}{3}+16=64

First, let's subtract 16 from both sides:

3(x-4)^\frac{4}{3}=48

Now, let's divide both sides by 3:

(x-4)^\frac{4}{3}=16

Remember that with fractional exponents, we can move the denominator into the root position. Therefore:

(\sqrt[3]{x-4})^4=16

Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!

\sqrt[3]{x-4} =\pm 2

Cube both sides. Since we're cubing, the plus-minus stays.

x-4=\pm 8

Add 4 to both sides.

x=\pm 8+4

Calculator:

x=8+4\text{ or } x=-8+4\\x=12\text{ or } x=-4

So, our answer is A.

And we're done!

7 0
3 years ago
Thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally
rusak2 [61]

Answer:

(a) The probability that the thickness is less than 3.0 mm is 0.119.

(b) The probability that the thickness is more than 7.0 mm is 0.119.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is 0.762.

Step-by-step explanation:

We are given that thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village are approximately normally distributed, with a mean of 5.0 millimeters (mm) and a standard deviation of 1.7 mm.

Let X = <u><em>thickness measurements of ancient prehistoric Native American pot shards discovered in a Hopi village.</em></u>

So, X ~ Normal(\mu=5.0,\sigma^{2} =1.7^{2})

The z-score probability distribution for the normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean thickness = 5.0 mm

           \sigma = standard deviation = 1.7 mm

(a) The probability that the thickness is less than 3.0 mm is given by = P(X < 3.0 mm)

    P(X < 3.0 mm) = P( \frac{X-\mu}{\sigma} < \frac{3.0-5.0}{1.7} ) = P(Z < -1.18) = 1 - P(Z \leq 1.18)

                                                           = 1 - 0.8810 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(b) The probability that the thickness is more than 7.0 mm is given by = P(X > 7.0 mm)

    P(X > 7.0 mm) = P( \frac{X-\mu}{\sigma} > \frac{7.0-5.0}{1.7} ) = P(Z > 1.18) = 1 - P(Z \leq 1.18)

                                                           = 1 - 0.8810 = <u>0.119</u>

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

(c) The probability that the thickness is between 3.0 mm and 7.0 mm is given by = P(3.0 mm < X < 7.0 mm) = P(X < 7.0 mm) - P(X \leq 3.0 mm)

    P(X < 7.0 mm) = P( \frac{X-\mu}{\sigma} < \frac{7.0-5.0}{1.7} ) = P(Z < 1.18) = 0.881

    P(X \leq 3.0 mm) = P( \frac{X-\mu}{\sigma} \leq \frac{3.0-5.0}{1.7} ) = P(Z \leq -1.18) = 1 - P(Z < 1.18)

                                                           = 1 - 0.8810 = 0.119

The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.

Therefore, P(3.0 mm < X < 7.0 mm) = 0.881 - 0.119 = 0.762.

4 0
3 years ago
What is not a description of slope?
Gelneren [198K]

Answer:

Option (d) is wrong.

Step-by-step explanation:

Slope is:

  • rise over run
  • The rate of change of a line
  • Change in y over the change in x
  • <em><u>The ratio of vertical change  to the horizontal change. </u></em>

It can be given by mathematically as follows :

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{and}\\\\m=\dfrac{dy}{dx}

Hence, the option which is not a description of slope is (d) "the ratio of horizontal change compared to vertical change"

7 0
3 years ago
Task: Multiplying and Dividing Expressions
koban [17]
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3 0
3 years ago
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