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MrRissso [65]
4 years ago
12

(5×10 exponent 8)/(2×10 exponent 6)​

Mathematics
1 answer:
iogann1982 [59]4 years ago
3 0
500,000,000 and 2,000,000

10 exponent 8 is 100000000 because it has 8 0s
multiply that by 5 to get 500,000,000

10 exponent 6 is 1000000 because it has 6 0s
multiply by 2 to get 2,000,000
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What is the total degree measure of the interior angles of a shape with 6 sides
elena-s [515]
The formula for calculating this is
(n - 2) x 180

So n = number of sides

(6 - 2) x 180

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So the total is 720°
8 0
3 years ago
Consider the following planes. x + y + z = 6, x + 7y + 7z = 6 (a) Find parametric equations for the line of intersection of the
Lelechka [254]

Answer:

a.x=6,y=-6t,z=6t

b.\theta=29.5^{\circ}

Step-by-step explanation:

We are given that

x+y+z=6

x+7y+7z=6

a.Substitute z=0

x+y=6...(1)

x+7y=6..(2)

Subtract equation (1) from equation (2)

6y=0

y=0

Substitute y=0 in equation(1)

x=6

The point (6,0,0) lie on a line.

r_0=(x_0,y_0,z_0)=(6,0,0)

Let A=

B=

A\times B=\begin{vmatrix}i&j&k\\1&1&1\\1&7&7\end{vmatrix}

A\times B=i(7-7)-j(7-1)+k(7-1)=-6j+6k

Therefore, the vector a'=(a,b,c)=

Line is parallel to vector a' and passing through the point (6,0,0).

The parametric equation is given by

x=x_0+at,y=y_0+bt,z=z_0+ct

Using the formula

The parametric equation is given by

x=6,y=-6t,z=6t

Angle between two plane

a_1x+b_1y+c_1z=d_1

and a_2x+b_2y+c_2z=d_2

cos\theta=\frac{(a_1,b_1,c_1)\cdot (a_2,b_2,c_2)}{\sqrt{a^2_1+b^2_1+c^2_1}\cdot \sqrt{a^2_2+b^2_2+c^2_2}}

Using the formula

cos\theta=\frac{(1,1,1)\cdot(1,7,7)}{\sqrt{1+1+1}\times \sqrt{1+7^2+7^2}}

cos\theta=\frac{1+7+7}{\sqrt 3\times 3\sqrt{11}}

cos\theta=\frac{15}{3\sqrt{33}}}=\frac{5}{\sqrt{33}}

\theta=cos^{-1}(0.87)=29.5^{\circ}

Where \theta in degree.

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Answer:

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