Answer:
<h3>48 feet</h3>
Step-by-step explanation:
First we need to get the total minutes used by the submarine from 10:57 A.M to 11:03 A.M. The total minutes used within the specified period of time is 6 minutes.
If its depth then changed at a rate of 8 feet per minute, the submarine depth after 6 minutes will be expressed as shown;
8 feet = 1minute
x feet = 6 minutes
cross multiply;
x * 1 = 8 * 6
x = 48 feet
Hence the submarine depth at 11.03AM is 48 feet
Answer:
The answer is 40 and I calculated it, it’s true
Step-by-step explanation:
I promise
Answer:
102°
Step-by-step explanation:
∠PQR = ∠PQS + ∠SQR
12x - 6 = 16 + 9x + 17
3x = 27
x = 9
∠PQR = 102°
Convert the timing into hours only:
11:15 = 11.25h
9:45 = 9.75h
11:45 = 11.75h
7:45 = 7.75h
10:45 = 10.75h
To find the average, we need to find the middle of these timing:
11.25 + 9.75 + 11.75 + 7.75 + 10.75 = 51.25
51.25 ÷ 5 = 10.25h = 10:15 am
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Answer: The average time it docks is 10:15 am.
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