IJKL is a rectangle, so opposite sides have the same length:
• IJ = KL ⇒ 6y - 6 = 2x + 20
• JK = IL ⇒ 3x + 21 = 6y
Substitute the second equation into the first and solve for x :
6y - 6 = 2x + 20
(3x + 21) - 6 = 2x + 20
3x + 15 = 2x + 20
x = 5
Solve for y :
3x + 21 = 6y
15 + 21 = 6y
36 = 6y
y = 6
Answer:
B. -6
Step-by-step explanation:
The common difference here is the difference between each term. Since it is an arithmetic sequence the difference between each term will be the same value.
So, from 45 (the 1st term) to 39 (the 2nd term), the difference is -6
From 39(the 2nd term) to 33, the difference is also -6.
Therefore, we know that the common difference fro this arithmetic sequence is -6.
Hope this helps and ask me any question if it does not :)
Answer:
Step-by-step explanation:
Here is the workings
2x+4y+6+2y-5+3x combine like terms
2x+3x+4y+2y+6-5
Step 2
2x+3x+4y+2y+6-5 Add the similar exponents
5x+4y+2y+6-5
5x+6y+6-5
Step 3
5x+6y+6-5 Add and subtract
Your answer would be 5x+6y+1
Answer: (B) x^3
Explanation:
If you compare the graphs of
all on the interval -1 < x < 0, you'll find that y = x^3 is the smallest when x = -1
Squaring a negative number leads to a positive result, and similarly that happens with x^4 as well. This is because x^4 = (x^2)^2.
Plugging x = -1 into x^3 leads to y = -1 as a result.
Answer:
the answer should be 18
Step-by-step explanation:
this isnt exactly hard when you get the first part with ST beeing 36 then you can just halve that and the answer is 18
