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kenny6666 [7]
3 years ago
14

I need help on 4-4a please

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:i think it is four

Step-by-step explanation:

I am 100% sure but I hope it helps'

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Veronica is choosing between two health clubs after how many months will the total cost for each health club be the same
Assoli18 [71]

Question:

Veronica is choosing between two health clubs. after how many months will the total cost for each health club be the​ same? yoga studio a: membership: $24.00 monthly fee: 21.50. yoga studio b: membership: $41.00 monthly fee: $17.25

Answer:

It takes 4 years for the total cost of each club to become equal

Step-by-step explanation:

Given:

For yoga studio A:

membership: $24.00

monthly fee: 21.50.

For yoga studio B:

membership: $41.00

monthly fee: $17.25

To Find:

Number of months after which the total cost for each health club be the​ same = ?

Solution:

Let   x be the number of months of membership, and   y  be equal the total cost.

For Yoga club A

y = 21.50 x + 24

For Yoga club B    

y = 17.25 x + 41.00

we know that the prices,   y , would be equal, we can set the two equations equal to each other.

21.50 x + 24 =17.25 x+ 41.00

Grouping the like terms,

21.50x - 17.25 x= 41.00 -  24

4.25x=17

x=\frac{17}{4.25}

x = 4

6 0
3 years ago
The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
Please answer if possible. Thanks!​
aliya0001 [1]

Answer:

0

Step-by-step explanation:

0 is the center of -4 and 4

7 0
3 years ago
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They are 6 away from eachother
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Question 10 of 20
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I can’t see planet a and b can you show me what it says
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