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3 years ago

Geometry please yelp

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

4 0

Answer:

https://www.yelp.com/

Step-by-step explanation:

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Enter a range of value for x.

zubka84 [21]

Answer:

-2 < x < 35

Step-by-step explanation:

We have that the larger side has a larger opposite angle and the smaller sides and a smaller opposite angle.

The opposite angle of the 14 unit side is 37 °.

The opposite angle of the 13-unit side is (x + 2) °.

Since 13 <14, it would be:

x + 2 <37

we subtract 2 on both sides

x <35

The value of x must be less than 35.

Now, to form a triangle, the angle must be greater than 0.

x + 2> 0

we subtract 2 on both sides

x> -2

The value of x must be greater than - 2.

Therefore the answer would be:

-2 <x <35

8 0

3 years ago

An expression is shown: 32 ÷ 4 What is the quotient expressed as a fraction?

harina [27]

Answer:

32/4

simplified is 8/1

Step-by-step explanation:

3 0

3 years ago

Does this graph have 10 or 9 squares, 10 or 9 years, I think I might be going insane

Yuliya22 [10]

Answer:

10 years

Step-by-step explanation:

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2 years ago

How to write two hundred thirty-eight thousand, five hundred thirty-three using suymbols please help

garri49 [273]

By symbol you mean number form? 238,533.

5 0

3 years ago

Find the vertical and horizontal asymptotes, domain, range, and roots of f (x) = -1 / x-3 +2.

gladu [14]

Answer:

Vertical asymptote: $x=3$

Horizontal asymptote: $f(x) =2$

Domain of f(x) is all real numbers except 3.

Range of f(x) is all real numbers except 2.

Step-by-step explanation:

Given:

Function:

$f (x) = -\dfrac{1 }{ x-3} +2$

One root, $x = 3.5$

To find:

Vertical and horizontal asymptote, domain, range and roots of f(x).

Solution:

First of all, let us find the roots of f(x).

Roots of f(x) means the value of x where f(x) = 0

$0= -\dfrac{1 }{ x-3} +2\\\Rightarrow 2= \dfrac{1 }{ x-3}\\\Rightarrow 2x-2 \times 3=1\\\Rightarrow 2x=7\\\Rightarrow x = 3.5$

One root, $x = 3.5$

Domain of f(x) i.e. the values that we give as input to the function and there is a value of f(x) defined for it.

For x = 3, the value of f(x) $\rightarrow \infty$

For all, other values of $x$ , $f(x)$ is defined.

Hence, Domain of f(x) is all real numbers except 3.

Range of f(x) i.e. the values that are possible output of the function.

f(x) = 2 is not possible in this case because something is subtracted from 2. That something is $\frac{1}{x-3}$ .

Hence, Range of f(x) is all real numbers except 2.

Vertical Asymptote is the value of x, where value of f(x) $\rightarrow \infty$ .

$-\dfrac{1 }{ x-3} +2 \rightarrow \infty$

It is possible only when

$x-3=0\\\Rightarrow x=3$

$\therefore$ vertical asymptote: $x=3$

Horizontal Asymptote is the value of f(x) , where value of x $\rightarrow \infty$ .

$x\rightarrow \infty \Rightarrow \dfrac{1 }{ x-3} \rightarrow 0\\\therefore f(x) =-0+2 \\\Rightarrow f(x) =2$

$\therefore$ Horizontal asymptote: $f(x) =2$

Please refer to the graph of given function as shown in the attached image.

5 0

3 years ago